A Andy005 Member Joined Mar 6, 2017 Messages 57 Location Gosford Gender Male HSC 2018 Nov 20, 2017 #2 y''=8x y'=4x^2+C m=tantheta m=tan45 m=1 Tangent at (-2,5) 1=4(-2)^2 +C C = -15 y'=4x^2 -15 y=4x^3/3 -15x + C 5=4(-2)^3/3 -15(-2) + C C = -43/3 Therefore y=4x^3/3 -15x -43/3
y''=8x y'=4x^2+C m=tantheta m=tan45 m=1 Tangent at (-2,5) 1=4(-2)^2 +C C = -15 y'=4x^2 -15 y=4x^3/3 -15x + C 5=4(-2)^3/3 -15(-2) + C C = -43/3 Therefore y=4x^3/3 -15x -43/3
