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  1. turtle_2468

    Complex Complexities!

    man.. isn't that mathematical enough for you? :P I could write out my first proof in terms of group theory/algebra. But that's not that helpful.. Case 1): You want a formal mathematical refutation of the claim that ln(-1)=0. In that case, suppose the statement were true. raise both sides to the...
  2. turtle_2468

    Complex Complexities!

    Basically, ln is defined as the inverse function to e^x. As such, its domain is all positive reals, and ln(-1) is hence an invalid function. Some might like to counter this by saying "but aha! What about e^ix = cos x + i sin x"? Well, in that argument, you could indeed get ln(-1). But this...
  3. turtle_2468

    The different sections of maths!

    I guess the main thing you missed there was algebra. This involves group theory, rings and stuff like that with elegant symbols and almost no real numbers... :) well, parts of it can do that anyway. And, if you put in stats as a subsection of mathematics, you should probably include applied...
  4. turtle_2468

    Exam Strategy

    I got 119 I think... I didn't do much work. But then, I learnt it back in year 10, and i was doing olympiad stuff for most of year 12. You SHOULD try to do papers - they help. So don't take me as an example.. EDIT: I think justchillin has the right approach. First 4 questions - make sure you...
  5. turtle_2468

    Exam Strategy

    I reckon it's pretty stupid... mark inefficient... if you hit your peak in the middle of the exam you SHOULD be doing 4,5,6 for most people anyway. Because you get a lot more marks on average from 4,5,6 - the doable-but-tricky questions - than 7,8 the questions which everyone assumes they can do...
  6. turtle_2468

    bit of a combination/permutation type question

    we're like pieces of nostalgia you get every so often... we pop up for a second, then you blink and we're gone again :P
  7. turtle_2468

    bit of a combination/permutation type question

    man.. no one learnt anything from my recursions lectures did they..
  8. turtle_2468

    inequalities questions..

    however, you probably can't assume cauchy anyway. Because it's nowhere near the reach of the syllabus you'd probably have to prove it (2 pages+) in order to use it.. The AM-GM is useful, and probably the only thing (short of them guiding you through something) that you'll need for 4U.
  9. turtle_2468

    bit of a combination/permutation type question

    I know the first one... busy right now, but if no one posts within a day bump it and I'll post up. Second one: Think about later. Ohh.. I'm assuming you don't know the answer.. if you do, get cracking on it guys who read these posts! :)
  10. turtle_2468

    q from UNSW maths assessment (from back in June I think?)

    basically, just writing a number as the product of prime numbers. So for example, 24 is not a prime number. but we can divide out by 2 to get 12, again by 2 twice to get 3 and by 3 to get 1 so 24 = 2^3*3. Similarly 120=2^2*3*5. Note that all the things which are raised to powers (here 2,3 and...
  11. turtle_2468

    q from UNSW maths assessment (from back in June I think?)

    Umm... ok. So n^3=m^5. Let n=p1^a1*p2^a2*p3^a3.....*pn^an. (too lazy... you know a1 is a subscript 1 etc) Obviously m has to have the same factors... so m=p1^b1*p2^b2*...*pn^bn. n^3=p1^3a1*p2^3a2*p3^3a3.....*pn^3an. m^5=p1^5b1*p2^5b2*...*pn^5bn. So because the two numbers are the...
  12. turtle_2468

    q from UNSW maths assessment (from back in June I think?)

    If you split n up using prime decomposition you will see that n has to be a power of 5. Therefore take 5th root of 3000000 - floor of that number should be possible values of (5th root of n) and hence the possible number of values n can take. This is the same as the number of values m can take...
  13. turtle_2468

    inequalities questions..

    as far as I know, no.
  14. turtle_2468

    inequalities questions..

    you mean the specific form of the cauchy inequality, otherwise known as the AM-GM? :)
  15. turtle_2468

    some simple questions

    closed. This is getting really unproductive..
  16. turtle_2468

    some simple questions

    A shorter version of what I wrote before: (0(00)*(10+01)(00)*(10+01)(01*0+1)*)+(1(00)*(10+01)(01*0+1)*) I know it's still longer than their answer but I understand how it works: the (10+01) is brilliant. It allows you to put in a 1 no matter the parity of 0's before it and preserve the...
  17. turtle_2468

    some simple questions

    lol... and you thought that one was short? Umm.. I think that + in your one means "or" right? In that case, I think that 0 is a valid string (take none of first, none of last, and the 0 in the middle one)... which is dodgy...
  18. turtle_2468

    some simple questions

    hmm. I just learnt about regular expressions :) http://www.cs.princeton.edu/introcs/72regular/ it's from princeton so it can't be that far off.. After thinking about this for a few minutes, I think that the answer IS quite ugly. For firstly you want to try to get rid of the at least two 1's...
  19. turtle_2468

    some simple questions

    Umm, this isn't a uni assignment is it? is it worth marks? I know the answer, I can describe it to you,but if you have a definition of "regular expression" that'd be nice..
  20. turtle_2468

    some simple questions

    hehe... the apology was aimed at you mostly I guess. But I guess I'm too competitive... I've done quite a few olympiad questions involving manipulation of strings etc, but if you're thinking about the more programming side of things, I'm not that sure... post up the question, if I don't know...
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