2008 Paper here (1 Viewer)

[ronnknee]

I took photos of the paper and then cropped them

Each of them are 640 px wide, wide enough to read the questions on the screen

Enjoy!

http://www.ronnknee.com/math_ext2.zip


PS: The paper was very different from past papers

 

[independantz]

Re: The Paper

URL does not work.

 

[midifile]

Re: The Paper

Yay

=]

 

[nsanchez01]

Re: The Paper

thankyou worked for meee

 

[midifile]

Re: The Paper

Worked for me

 

[independantz]

Re: The Paper

Worked for me

Yeah he changed the url

 

[wil123]

Re: Download the Paper here

PS: The paper was very different from past papers

Good or bad?

 

[ronnknee]

Re: The Paper

Yeah he changed the url

No I didn't
I only added the description

 

[ronnknee]

Re: Download the Paper here

Good or bad?

Very bad

 

[wil123]

Re: Download the Paper here

Very bad

Thanx

 

[miche11e]

Re: Download the Paper here

ive got it in a pdf here if you want?
hopefully this works?
Sorry in advance for my pencil scribblings - they may be helpful however haha

 

[nottellingu]

Re: Download the Paper here

Henry guy with same dp as me is a troll

 

[nottellingu]

Re: Download the Paper here

That paper fucked me over
I was getting like 95-105 raw in past papers. But then i got analed by that conics q...the gradients werent equal so kept trying and wasted valuable time and ran out. now im gonna get like in the 80;s

Ppl at my school with ranks below me think they got 105 +...good signs :rofl: .....hope i get moderated nicely PLZZZZ BOS

 

[ronnknee]

Re: Download the Paper here

That paper fucked me over
I was getting like 95-105 raw in past papers. But then i got analed by that conics q...the gradients werent equal so kept trying and wasted valuable time and ran out. now im gonna get like in the 80;s

Ppl at my school with ranks below me think they got 105 +...good signs :rofl: .....hope i get moderated nicely PLZZZZ BOS

That was my original approach as well, proving the gradients equal
But then I couldn't get anything
On the blank page on the left, I assumed that the gradients were equal and tried to come up with another expression and then I realised that it would look like the equation if I had subbed M into the line OT
It worked when I did that because I get 0 = 0 which means M satisfies the equation and therefore lies on line OT and therefore they are collinear

 

[nottellingu]

I think u can just use the eqn that t lies on....that equation is in the for y=mx ...which means that it HAS TO pass through the origin...and then u can show that its gradient "m"...and then find the gradient of 0M and show they are equal.

I didnt get it at the time but i think that above is the easiest approach.
I spent lik 15 mins on that fucking q ...i never thought it would come to this but screw u maths !

 

[willemhenskens]

I think u can just use the eqn that t lies on....that equation is in the for y=mx ...which means that it HAS TO pass through the origin...and then u can show that its gradient "m"...and then find the gradient of 0M and show they are equal.

I didnt get it at the time but i think that above is the easiest approach.
I spent lik 15 mins on that fucking q ...i never thought it would come to this but screw u maths !

don't be angry this is the reason for assessment. you will get scaled nicely

life has its ways of working everything out.

 

[willemhenskens]

Re: Download the Paper here

I HAVE ONLY MATHS AND PHYSICS IN MY HSC LIBRARY

pretty sure u need notes/books/time for other subjects too?
[edit] so u know, u never actually said that ^^ but u have a very telling sig [/edit]
[edit 2]admittedly, all other subjects are bullshit other than 4unit and phys [/edit 2]

 

[yanerkang]

a

 

[pyrodude1031]

Solutions by Terry Lee.