• Congratulations to the Class of 2024 on your results!
    Let us know how you went here
    Got a question about your uni preferences? Ask us here

2016ers Chit-Chat Thread (28 Viewers)

Status
Not open for further replies.

Paradoxica

-insert title here-
Joined
Jun 19, 2014
Messages
2,556
Location
Outside reality
Gender
Male
HSC
2016
Is it possible to construct a bijective function in which the codomain consists strictly of transcendental numbers?
 

leehuan

Well-Known Member
Joined
May 31, 2014
Messages
5,805
Gender
Male
HSC
2015
In fact, this can be said for most (or at least many) of the HSC maths topics, can't it?
At least with stuff such as Thales' theorem the statement of the theorem itself gets memorised. Here, they just say something like "therefore x = ..." without no justification. But yep.

Well that's the same with the intermediate value theorem and the fundamental theorem of calculus. Theres no point formalising things and naming them properly if students aren't doing rigorous analysis. (Which they cannot even begin to do without proper construction of the reals and discussion of limits, which is not at all feasible for a secondary school course).

What is important though, is that everything done in HSC mathematics CAN be made rigorous with sufficient knowledge. This is why they consult with academics when it comes to writing HSC MX2 exams.
Same principle I guess, but at least they are shown that it is indeed called the fundamental theorem of calculus. They take it granted from there.
____________________________

Obviously those questions in the HSC are not made by ordinary maths teachers. Whilst I believe any maths teacher that isn't bad can do the entire paper, not that many are going to be able to create those targetting band 6/E4 type questions.

Even my teacher once alluded to "some professor making up this question whilst he was having a cup of coffee..."
 

seanieg89

Well-Known Member
Joined
Aug 8, 2006
Messages
2,662
Gender
Male
HSC
2007
but at least they are shown that it is indeed called the fundamental theorem of calculus.
Less often than you might think. A pretty large proportion of my ex-students had not heard that name, and just knew that "differentiation and integration were inverse to each other."
 

leehuan

Well-Known Member
Joined
May 31, 2014
Messages
5,805
Gender
Male
HSC
2015
Exactly. :p

Bijective function - The function is both injective and surjective
- Surjective - For every value in the codomain, there exists at least one corresponding value in the domain
- Injective - For every value in the domain, there exists at most one corresponding value in the codomain.
*Domain - The set of allowable input values of a given function

Codomain - The set of allowable output values of a given function

Transcendental numbers - A subset of all irrational numbers; the set of irrational numbers that cannot be expressed as the roots of any non-zero polynomial with rational coefficients.
-Rational numbers - The set of all numbers that can be expressed in the form p/q, where p and q are integers with the exclusion q can't equal to 0

Please tell me you knew two things in that at least
 

leehuan

Well-Known Member
Joined
May 31, 2014
Messages
5,805
Gender
Male
HSC
2015
Less often than you might think. A pretty large proportion of my ex-students had not heard that name, and just knew that "differentiation and integration were inverse to each other."
That's quite horrific. Even maths in focus mentions the name Fundamental Theorem of Calculus
 

InteGrand

Well-Known Member
Joined
Dec 11, 2014
Messages
6,109
Gender
Male
HSC
N/A
Less often than you might think. A pretty large proportion of my ex-students had not heard that name, and just knew that "differentiation and integration were inverse to each other."
I think it is also common for HSC students to think something like d/dx ∫f(x) dx = f(x) is an application of FTC.
 

MilkyCat_

Active Member
Joined
Oct 3, 2014
Messages
602
Gender
Female
HSC
2016
Exactly. :p

Bijective function - The function is both injective and surjective
- Surjective - For every value in the codomain, there exists at least one corresponding value in the domain
- Injective - For every value in the domain, there exists at most one corresponding value in the codomain.
*Domain - The set of allowable input values of a given function

Codomain - The set of allowable output values of a given function

Transcendental numbers - A subset of all irrational numbers; the set of irrational numbers that cannot be expressed as the roots of any non-zero polynomial with rational coefficients.
-Rational numbers - The set of all numbers that can be expressed in the form p/q, where p and q are integers with the exclusion q can't equal to 0

Please tell me you knew two things in that at least
Hahaha yeah I knew two
 

seanieg89

Well-Known Member
Joined
Aug 8, 2006
Messages
2,662
Gender
Male
HSC
2007
Is it possible to construct a bijective function in which the codomain consists strictly of transcendental numbers?
Yes. The function with domain {0} and codomain {e}.

For something less silly, I will assume you are asking whether or not there exists a bijection from the transcendentals to the reals. This is also true. In fact we can replace the transcendentals with any co-countable set S.

Picture the argument as follows:

Enumerate the elements of the countable complement of S as x_1,x_2,...

Enumerate an arbitrary countable subset of S as y_1,y_2,...

Now map y_{2k-1} to x_k, map y_{2k} to y_k, and leave all other elements of S fixed.

This map is then a bijection from S to R.
 

seanieg89

Well-Known Member
Joined
Aug 8, 2006
Messages
2,662
Gender
Male
HSC
2007
That's quite horrific. Even maths in focus mentions the name Fundamental Theorem of Calculus
Eh. I don't think it's that big a deal if students don't know what things are called in high school. I'd much rather them develop good problemsolving skills than learn the names of theorems.

FTC in particular refers to so many different theorems as we generalise notions of integration/differentiation and consider inversion in the two different orders.
 

Nailgun

Cole World
Joined
Jun 14, 2014
Messages
2,193
Gender
Male
HSC
2016
I think it is also common for HSC students to think something like d/dx ∫f(x) dx = f(x) is an application of FTC.
Isn't the fundamental theory thingo that for a function f(x) where F(x) is the primitive function, the definite integral between b and a of f(x) is equal to F(b)-F(a)

inb4 completely wrong lel
 

Paradoxica

-insert title here-
Joined
Jun 19, 2014
Messages
2,556
Location
Outside reality
Gender
Male
HSC
2016
Eh. I don't think it's that big a deal if students don't know what things are called in high school. I'd much rather them develop good problemsolving skills than learn the names of theorems.

FTC in particular refers to so many different theorems as we generalise notions of integration/differentiation and consider inversion in the two different orders.
This.

Quite frankly, the majority of teachers don't care about the how and why of mathematics, only the what.

And we wonder why our mathematics is falling behind the rest of the world's...
 

leehuan

Well-Known Member
Joined
May 31, 2014
Messages
5,805
Gender
Male
HSC
2015
Isn't the fundamental theory thingo that for a function f(x) where F(x) is the primitive function, the definite integral between b and a of f(x) is equal to F(b)-F(a)

inb4 completely wrong lel
There's actually 2 statements in the fundamental theorem of calculus. That's the second.
 

iforgotmyname

Metallic Oxide
Joined
Jun 16, 2015
Messages
733
Gender
Male
HSC
2015
The more you cram the less effective it becomes. Fact.

Knowledge is inversely proportional to cramming
No, thats too general. Different methods for study works with different people. Stop trying to exert your ideals on others.
 

leehuan

Well-Known Member
Joined
May 31, 2014
Messages
5,805
Gender
Male
HSC
2015
No, thats too general. Different methods for study works with different people. Stop trying to exert your ideals on others.
Except I'm not.

I have never seen a crammer beat every single person who actually studied in their cohort.
 
Status
Not open for further replies.

Users Who Are Viewing This Thread (Users: 0, Guests: 28)

Top