2026 HSC CHAT (17 Viewers)

isho-3

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Guys how to find an equation for an exponential graph? I used ai, google n youtube n i get the gist but im not sure this is what ik
y=a^x
when x = 0, y=1
if the curve goes through, (0,1) and (-2,16) we can get the following
16= a^-2
it then becomes
1/16= 1/a^2
square root 1/16 it then becomes 1/4 which is the answer
did i do the steps correctly? since i did it right it seems like i get it but im a bit confused can someone provide me w another graph so i can try n find the equation? Or just explain/give me a youtube video?
plz i have a test on wednesday n non-linear is one topic out of 4 🙏🙏
yeah seems like you did it correct!! and the way id have done it too, so i think you're on a pretty good track?
 

Shavi Masee

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Guys how to find an equation for an exponential graph? I used ai, google n youtube n i get the gist but im not sure this is what ik
y=a^x
when x = 0, y=1
if the curve goes through, (0,1) and (-2,16) we can get the following
16= a^-2
it then becomes
1/16= 1/a^2
square root 1/16 it then becomes 1/4 which is the answer
did i do the steps correctly? since i did it right it seems like i get it but im a bit confused can someone provide me w another graph so i can try n find the equation? Or just explain/give me a youtube video?
plz i have a test on wednesday n non-linear is one topic out of 4 🙏🙏
You did it correctly!!
Your aim is to get 'a' by itself and while substituting the numbers you have been given into the equation. Is there any particular part that ur confused abt?
 

jane1820

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You did it correctly!!
Your aim is to get 'a' by itself and while substituting the numbers you have been given into the equation. Is there any particular part that ur confused abt?
THE THING IS IDK WHAT IM CONFUSED ABT TOO 😭 im good at math n can do it but when i was solving it i just paused mid way n was like ‘huh? This is the right answer but what?’
i think im just not confident thats all 👎
 

isho-3

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Ok thx
do u have any graphs? One is enough bc i have practise papers for my test i just need one graph to be 100% sure i can do this
wait do you want a graph of that question you mentioned or just any anotated graph of an exponential curve in general, bc i think i have a few of those from my maths class i made
 

Shavi Masee

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THE THING IS IDK WHAT IM CONFUSED ABT TOO 😭 im good at math n can do it but when i was solving it i just paused mid way n was like ‘huh? This is the right answer but what?’
i think im just not confident thats all 👎
You could use desmos to see how the graph moves by putting random numbers in, It helped me a bunch for my exam. Desmos.
I think isho is giving you some numbers so i won't bother<3
 

jane1820

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I use desmos to see how the graphs move by putting random numbers in, It helped me a bunch for my exam. Desmos
My teacher highly (also) recommends desmos n this other website but i dont want to look at a graph n how it moves i want to understand how it happens
also my textbook has answers so i just check the end of the book
is desmos actually that useful?
 

Shavi Masee

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My teacher highly (also) recommends desmos n this other website but i dont want to look at a graph n how it moves i want to understand how it happens
also my textbook has answers so i just check the end of the book
is desmos actually that useful?
YES veryy!! (atleast for me), if you know how to use it/ what you're looking for.

When I put the random numbers in, i compare it to another graph with a different equation. You end up finding a pattern and that's how I understand it. Not sure if it works for everyone or if that's what you mean.
 

jane1820

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View attachment 44151View attachment 44152
the first one is one i made just now, and the other 3 are ones i made for sketching exercises in-class if you want to try em out
y=a^x
two points (0,1) and (3,27/8)
therefore when x=0, y=1
when x=3, y=27/8
using y=a^3: 27/8= a^3
Cube root 27/8 = 3/2
therefore a= 3/2
therefore y=(3/2)^x

ALSO OMG UR LINES R SO NEAT WHATTTTT MY CURVES N SO SAD 😭👎
 

isho-3

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y=a^x
two points (0,1) and (3,27/8)
therefore when x=0, y=1
when x=3, y=27/8
using y=a^3: 27/8= a^3
Cube root 27/8 = 3/2
therefore a= 3/2
therefore y=(3/2)^x

ALSO OMG UR LINES R SO NEAT WHATTTTT MY CURVES N SO SAD 😭👎
yep, correct!!! and THANKS!!!!!! it's a skill developed from studying & drawing a frankly concerning amount of graphs (not just expo but graphing. any algebraic equation) for math tuition (i am still doing so. help). i have almost perfected the art of balancing pressure & wrist movemen+steadiness,,,,,,,
 

jane1820

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yep, correct!!! and THANKS!!!!!! it's a skill developed from studying & drawing a frankly concerning amount of graphs (not just expo but graphing. any algebraic equation) for math tuition (i am still doing so. help). i have almost perfected the art of balancing pressure & wrist movemen+steadiness,,,,,,,
so good whattttt
also for ur graphs shouldnt ur curves/lines have an arrow at the ends to indicate its still expanding?
 

isho-3

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so good whattttt
also for ur graphs shouldnt ur curves/lines have an arrow at the ends to indicate its still expanding?
good point, i usually don't bc i'm used to graphing w/o it plus to me it looks a little janky (and thankfully my school allows it)
 

isho-3

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i only have math and sci this term (all ready did both), i have some careers bullshit as well but that does not count, next term got yearlys for everything in week 5/6 thougho_O
funnily enough, next term is actually just mostly cruising for me lmao. i've got like. 3 assessments (exam or project) at most next term and they're all due around the start of the term, which means we've got basically dud low-stakes subjects for the rest of the term and i can focus on preparing for y11
 

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