2026 HSC CHAT (11 Viewers)

[No_Kaeya?!]

E

F

 

[Study to success]

F

G

 

[No_Kaeya?!]

G

H

 

[Study to success]

H

I

 

[No_Kaeya?!]

I

J

 

[ellurbee]

I think my English teacher either likes me a lot, or is genuinely concerned for me-

 

[Study to success]

J

K

 

[Study to success]

I think my English teacher either likes me a lot, or is genuinely concerned for me-

did u give her another 1984 theory lol

 

[ellurbee]

did u give her another 1984 theory lol

Nah not this time i think i'm all theory out...

 

[Study to success]

Guys how do I find the negative values. Do I minus 360 from each value

 

[Bendwhat?_over]

View attachment 50875
Guys how do I find the negative values. Do I minus 360 from each value

pi is 180, so your range is [-180, 180]
From 0-180, find where tan is positive
From 0 - -180, find where tan is negative.
Does that give the right answer? I'm honestly not too sure if that's how it's solved.

 

[Study to success]

pi is 180, so your range is [-180, 180]
From 0-180, find where tan is positive
From 0 - -180, find where tan is negative.
Does that give the right answer? I'm honestly not too sure if that's how it's solved.

ik that but Idk how to find the other values

 

[No_Kaeya?!]

ik that but Idk how to find the other values

is it like
not just the reverse?

 

[Study to success]

is it like
not just the reverse?

so do I just go -45+180

 

[asddsa]

You're my #1 fan after just one message?

yes ofc

 

[asddsa]

i cant believe u noticed me.. AH

 

[No_Kaeya?!]

so do I just go -45+180

i think so? that or its just the negative/positiver version of that function.

 

[f7eeting]

the usual period for tanx is pi (180 degrees) but for tan3x the period changes to 1/3 pi (or 60 degrees). this means you can expect the same answer, ie a point on the tan graph that equals 1 on the y axis every 60 degree increments/rotations if that makes sense.
tan3x=1, and since tan45=1, you can conclude that 45=3x, so x=15.
knowing your first value of tan3x, you can then just add/subtract 60 degrees continually from 15 degrees and exclude any values that exceed your domain

 

[jane1820]

View attachment 50875
Guys how do I find the negative values. Do I minus 360 from each value

Here i was bored

 

[Study to success]

Here i was bored
View attachment 50876

thanksss