2Unit Mathematics 2007 Solutions (1 Viewer)

[Poad]

For what its worth, I multiplied it by 4, but I had the initial working completely wrong so it didnt matter anyway. So yeah, I thought you had to multiply by 4, but I suck at probability so I dunno...

 

[iEdd]

If you put 1/4 x 39/51, then you have to multiply by 4. This is because 1/4 is the chance of picking a card from a particular suit. x4 makes it ANY suit. It's easier to just say the first card can be anything and call it 1 x 39/50. Get it?

 

[watto9]

U r a pro writing up all the answers i wouldnt be bothered haha, but according to the solutions i should get around 110/120. thanks mate for the effort u put in

 

[0nikki0]

Thanks for the solutions =]

I've only looked at the couple of questions that i couldn't do, i don't know if i want to look at the whole thing and see what i got, just yet anyway. But thank you =]

 

[morjoel]

Yeah good stuff! I got 113/120

Quite happy but it was all silly things I miswrote or some other mistake.

 

[desipryde]

if dose working outs r correct den i got 92/120 =( BLOOD HELL

 

[jakree_golf]

awww nooo my band 6 is gone!!! would prob be getting around 85-93/120 (93 according to the solution but must have prob made some silly mistakes = =)

anyway, Thanks Heaps!!!!

 

[the-1-n-only-me]

yer lol

lol. fair 'nuff. good work tho. still havent looked at it yet :rofl:

 

[yehdatsrite]

Thanks mate, great post =]
you made q10 (b) look pretty smooth, couldnt figure it out under exam stress though =_=
would it be possible if u could scan the paper online, ive lost mine already xD

Hey all,

I took the time to write up some solutions (hand written).

Let me know what you think of my answers..do you agree or disagree?

B.t.w. I did all these in the exam apart from the final question 10(b)(ii).


Thanks.

Note: Q4(c)(iv) asked for major sector; I found the minor sector. Therefore, the correct answer should be: 5n/2 units squared.
(this answer was later found in part (v) i.e. A(Shaded-Circle-C)
Thanks for letting me know.

Link: http://members.optusnet.com.au/mattzada/2unit_maths_2007_solutions.pdf
Note: changed the URL due to bandwidth usage

 

[DenJe]

Cheers for the Solutions.....probs 80-90/120.....depending on how many marks for working :S

 

[cc =)]

Hey all,

I took the time to write up some solutions (hand written).

Let me know what you think of my answers..do you agree or disagree?

B.t.w. I did all these in the exam apart from the final question 10(b)(ii).


Thanks.

Note: Q4(c)(iv) asked for major sector; I found the minor sector. Therefore, the correct answer should be: 5n/2 units squared.
(this answer was later found in part (v) i.e. A(Shaded-Circle-C)
Thanks for letting me know.

Link: http://members.optusnet.com.au/mattzada/2unit_maths_2007_solutions.pdf
Note: changed the URL due to bandwidth usage

not sure if i agree with you on 9c) (ii) and (iii) . For 9c) (ii), she increases her annual contribution by 6% each year. So, her first contribution is A1=1000(1.06) for when the son was first born, i.e. hes zero. The second contribution made is when he is one, and the value she invests is a 6% increase of the previous year plus another 6% for the interest; i.e. A2= A1( 1.06)(1.06)= 1000(1.06)^3 and so on. Am i right ? If not then please correct. I checked my answers with yours and i made so many silly mistakes =( wanting a band 6 but not so sure now ..

 

[mattzada]

Hey, in part (ii)

The first contribution she makes gains interest for 3 years:
A1 = 1000(1.06)^3

The second contribution she makes is increased by 1.06, and gains interest for 2 years only:
A2 = 1000(1.06)x(1.06)^2 = 1000(1.06)^3

The third ..... is increased by 1.06^2 and gains interest for 1 year:
A3 = 1000(1.06)^2x(1.06) = 1000(1.06)^3

A(TOTAL) = A1 + A2 + A3 = 3x1000(1.06)^3
A(N) = nx1000(1.06)^n

I hope that clears things up

 

[Fish Sauce]

Ah, I buggered up that question. Damn it, those are one of my strengths as well. Your answer's right. I think I kept adding 1000x1.06 so I ended up with 1000 times a geometric series.

 

[aznteenager]

hm for question 7b)ii
me and my friend end up with the same result which was 1 less from what you got...
i dono who got it right..
cuz like i went onto the trouble to do it bit by bit...
that put me on the stress of not enough time and end up losing my concentration for question 10b)
man i walked out and i figured out how to do it>.<
owel thanks for the post=)

 

[PulpDood]

For 8a)ii I wrote during October since it is within the 10th month (10.644) would that be correct?

And if it hasn't been said (cbf reading whole thread), for 7 (b)i couldn't you just make cuberoot(3)=sinx/cosx therefore, cuberoot(3)=tanx???

 

[Yamini]

THANKYOU SOO MUCH!!!

i think off your thing i got 100+ ish heaps stoked

thanks again for posting...

 

[Fish Sauce]

For 8a)ii I wrote during October since it is within the 10th month (10.644) would that be correct?

And if it hasn't been said (cbf reading whole thread), for 7 (b)i couldn't you just make cuberoot(3)=sinx/cosx therefore, cuberoot(3)=tanx???

I did the same as you for both questions. Good news is yes that's a perfectly fine way to do question 7. Bad news is I think we screwed up with October.

 

[mattzada]

I did the same as you for both questions. Good news is yes that's a perfectly fine way to do question 7. Bad news is I think we screwed up with October.

yer...1.0 months means January has finished...so 10.0 months means October has finished...i.e. we are in November

 

[crono26]

good work! i got all the same answers as you except the money in the bank and the last one! 110/120 for me i was freaking out if i should look at them or not

 

[-pari-]

mmm....i knew i'd get the displacement graph in Q10 wrong.