3D - Trig Q diagram needed (1 Viewer)

axwe7 · Jun 27, 2016

An aeroplane flies horizontally due east at a constant speed of 240km/hr, From a point P on the ground, the bearing of the plane at one instant is 311 T, and 3 min later, the bearing of the plane is 073 T, whilst its elevation then is 21. If h metres is the altitude of the plane, show that h = 12000 sin 41 tan 21 cosec 58 and calculate h to nearest metre

*21 = 21 degrees

axwe7 · Jun 27, 2016

Answer is 3564m

davidgoes4wce · Jun 27, 2016

$\angle DPC=122^\circ$

$\angle PDC=41^\circ$

$DC=12000 metres$

$$ Using the sine Rule,$ \frac{sin 122^\circ}{12000}=\frac{sin 17^\circ}{CP}$

$CP=9283.33 \ metres$

$tan 21^\circ= \frac{h}{CP}$

$h=$ 3564 metres $$

3D - Trig Q diagram needed (1 Viewer)

axwe7

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