• Best of luck to the class of 2024 for their HSC exams. You got this!
    Let us know your thoughts on the HSC exams here
  • YOU can help the next generation of students in the community!
    Share your trial papers and notes on our Notes & Resources page
MedVision ad

4u Mathematics Marathon v2.0 (1 Viewer)

P

pLuvia

Guest
Time to start this again, point of this thread is to test each other's maths skills, general revision etc.

General rule: A person posts up a question (not homework-help questions) and then another person answers it in spoilers and after they answer they put up another question for the next person to answer

How to do spoilers : [spoiler ]Like this[/spoiler ], but without the spaces in between the brackets so without it, it would be something like this
Like this

I'll start off to get the ball rolling, last question from the previous marathon

Question

How many possible four letter words can be selected from the word MATHEMATICS?
 
Last edited by a moderator:

kony

Member
Joined
Feb 10, 2006
Messages
322
Gender
Undisclosed
HSC
2007
isn't it a bit early to ask this stuff?

like the whole methods of counting thing - i think most schools won't have touched on this yet.

and why is this in ext2? isn't this .. 3unit?

and you copied this straight from a hsc paper lol (i dont remember how many units it was though)
 
P

pLuvia

Guest
kony said:
isn't it a bit early to ask this stuff?

like the whole methods of counting thing - i think most schools won't have touched on this yet.

and why is this in ext2? isn't this .. 3unit?

and you copied this straight from a hsc paper lol (i dont remember how many units it was though)
I did? I've never encountered this I don't think, I made it up on the spot
 

Mill

Member
Joined
Feb 13, 2003
Messages
256
Gender
Male
HSC
2002
pLuvia said:
How many possible four letter words can be selected from the word MATHEMATICS?
There are 8 unique letters in the word "Mathematics": A, C, E, H, I, M, S, T. We desire 4 letter words. There are 8P4 = 1680 such words.
 

Mill

Member
Joined
Feb 13, 2003
Messages
256
Gender
Male
HSC
2002
My Question:

The sum of the ages of the four children of a family is equal to half the age of their father. The difference of the squares of the ages of the oldest and youngest children is equal to the age of the father, which is also equal to twice the sum of the differences of the squares of the ages of the two younger and two older children. In sixteen years time, the sum of the ages of the children will exceed the age of their father by his present age. Find the age of every member of this family.
 
P

pLuvia

Guest
I was thinking along the lines of

Case 1: 8 unique letter - 8P4=1680
Case 2: 2 of the same letters plus two different letters - 3C1*7C2*4!/2!=756
Case 3: 2 pairs of the same letters - 3C2*4!/2!2!=18

Hence the number of words would be 1680+756+18=2454
 

Mill

Member
Joined
Feb 13, 2003
Messages
256
Gender
Male
HSC
2002
pLuvia said:
I was thinking along the lines of

Case 1: 8 unique letter - 8P4=1680
Case 2: 2 of the same letters plus two different letters - 3C1*7C2*4!/2!=756
Case 3: 2 pairs of the same letters - 3C2*4!/2!2!=18

Hence the number of words would be 1680+756+18=2454

Oh yah you are clearly correct. For some reason when I wrote the answer I thought you had specified that letters could not be used more than once.
 

Riviet

.
Joined
Oct 11, 2005
Messages
5,593
Gender
Undisclosed
HSC
N/A
Mill said:
which is also equal to twice the sum of the differences of the squares of the ages of the two younger and two older children.
Could you clarify what you mean by this? :p
 
P

pLuvia

Guest
I think that means:

Let the younger brothers be a and b like wise with the older children let them be x and y, from my interpretation it means

2[(a2-b2)+(x2-y2)]
 

Mill

Member
Joined
Feb 13, 2003
Messages
256
Gender
Male
HSC
2002
pLuvia said:
I think that means:

Let the younger brothers be a and b like wise with the older children let them be x and y, from my interpretation it means

2[(a2-b2)+(x2-y2)]
Yes, if you're assuming that from eldest to youngest we have: a,b,x,y.
 

Slidey

But pieces of what?
Joined
Jun 12, 2004
Messages
6,600
Gender
Male
HSC
2005
ravdawg, post a question :)

Try and keep it within the scope of the 4u syllabus, of course.
 

ravdawg

Member
Joined
Mar 7, 2006
Messages
46
Location
Wollongong
Gender
Male
HSC
2007
Oh yeah, sorry, i kinda posted teh answer and completely forgot to put up a new question.

Ok here goes, not really a hsc type question but yeah...

Two cars are 1.5km away from each other. Both are travelling at a constant velocity to each other, one at 5m/s and the other 10m/s. There is a plane in between them, starting at one of the cars which travels at 20m/s. Every time it reaches one of the cars it turns around insantaneously and goes in the opposite direction till it meets the other car etc. When the two cars meet, how far would the plane have travelled in metres.
 

LoneShadow

Uber Procrastinator
Joined
May 24, 2004
Messages
877
Gender
Undisclosed
HSC
N/A
although you mention that the question is not HSC type; but even a general maths student knows how to that question. Could probably bet a year 10 kid could do that question. All you need is a pencil that can last long enough to draw a few semi straight lines back and forth.

It doesn't belong in Ext2 section. :p


that being said here are a few question that shouldn't probably be posted here either :eek::

(1) Show that for all positive x and y: Exp(x+y)/(xy)>=Exp(2).
(2) Fow what value of k does the equation Exp(2x)=kSqrt(x) has exactly one solution?
(3) For which positive number a is it true that a^x>=1+x for all x?

[questions randomly chosen from a general calculus book]
 

ravdawg

Member
Joined
Mar 7, 2006
Messages
46
Location
Wollongong
Gender
Male
HSC
2007
LoneShadow said:
although you mention that the question is not HSC type; but even a general maths student knows how to that question. Could probably bet a year 10 kid could do that question. All you need is a pencil that can last long enough to draw a few semi straight lines back and forth.

It doesn't belong in Ext2 section. :p


that being said here are a few question that shouldn't probably be posted here either :eek::

(1) Show that for all positive x and y: Exp(x+y)/(xy)>=Exp(2).
(2) Fow what value of k does the equation Exp(2x)=kSqrt(x) has exactly one solution?
(3) For which positive number a is it true that a^x>=1+x for all x?

[questions randomly chosen from a general calculus book]
If you're trying to figure out the answer to this question by drawing lines back and forward you are making it hard for yourself. The reason i gave this question is that you can do it in one line and about 5 seconds if you use your head a bit...
 

vafa

Member
Joined
Mar 16, 2006
Messages
302
Gender
Undisclosed
HSC
N/A
I have an interesting question:

Prove that Sigma (from k=0 to n) coskx={cos(nx/2)sin((x(n+1))/2)}/sin(x/2)

and sigma (from k=0 to n) sinkx={sin(nx/2)sin((x(n+1))/2)}/sin(x/2)

note: there are lots of ways to show those two identities.but the main ways are by using mathematical induction or by using the property of complex numbers (Euler's equation e^(ix)=cosx+isinx)). but mathematical induction needs more work so i suggest to use euler's equation
 

kony

Member
Joined
Feb 10, 2006
Messages
322
Gender
Undisclosed
HSC
2007
ravdawg said:
Oh yeah, sorry, i kinda posted teh answer and completely forgot to put up a new question.

Ok here goes, not really a hsc type question but yeah...

Two cars are 1.5km away from each other. Both are travelling at a constant velocity to each other, one at 5m/s and the other 10m/s. There is a plane in between them, starting at one of the cars which travels at 20m/s. Every time it reaches one of the cars it turns around insantaneously and goes in the opposite direction till it meets the other car etc. When the two cars meet, how far would the plane have travelled in metres.
it takes the cars 1500/(5+10) seconds to meet. in that time, the plane hasnt stopped moving. therefore, the plane has travelled 20 * 1500/(5+10) meters.

20*1500/15 = 20*100 = 2000m = 2 km.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top