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4U Revising Game (1 Viewer)

Drongoski

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Mr harism

Thank u. In my hurry, I dropped the x^n. I've amended my solution.
 
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Trebla

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Would've been much simpler if you just do:



Question:

Suppose f(x) = 1/x + sin²(πx) / πx². By considering the first derivative, prove that f(x) is decreasing for x > 0.
 
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harism

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yea i see drongoski.
its a nice solution.
(call me haris, lol)

btw, trebla.
my god.
gurmies was right about you.
your epic.

i would never have seen that solution coming. =O
good work!
 
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azureus88

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[maths]f'(x)=-\frac{1}{x^2}+\frac{1}{n}\frac{2nx^2\sin(nx)\cos(nx)-2x\sin^2(nx)}{x^4}\\=-\frac{1}{x^2}+\frac{1}{n}\frac{nx\sin(2nx)-2\sin^2(nx)}{x^3}\\=\frac{-nx+nx\sin(2nx)+\cos(2nx)-1}{nx^3}\\=\frac{nx(\sin(2nx)-1)+(\cos(2nx)-1)}{nx^3}\\<0\,\,$for$\,\,x>0\\$since$\,\,-1\leq \sin(2nx)\leq 1\,\,$and$\,\,-1\leq \cos(2nx)\leq 1\\$and when$\,\,\sin(2nx)=1,\cos(2nx)\neq 1[/maths]
 
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gurmies

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[maths]f'(x)=-\frac{1}{x^2}+\frac{1}{n}\frac{2nx^2\sin(nx)\cos(nx)-2x\sin^2(nx)}{x^4}\\=-\frac{1}{x^2}+\frac{1}{n}\frac{nx\sin(2nx)-2\sin^2(nx)}{x^3}\\=\frac{-nx+nx\sin(2nx)+\cos(2nx)-1}{nx^3}\\=\frac{nx(\sin(2nx)-1)+(\cos(2nx)-1)}{nx^3}\\<0\,\,$for$\,\,x>0\\$since$\,\,-1\leq \sin(2nx)\leq 1\,\,$and$\,\,-1\leq \cos(2nx)\leq 1\\$and when$\,\,\sin(2nx)=1,\cos(2nx)\neq 1[/maths]
I think it's pi, not n...?
 
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harism

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Would've been much simpler if you just do:



Question:

Suppose f(x) = 1/x + sin²(πx) / πx². By considering the first derivative, prove that f(x) is decreasing for x > 0.
trebla, put us out of our misery.
is it a pi or an n?

thanks.
 

Drongoski

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trebla, put us out of our misery.
is it a pi or an n?

thanks.
Don't think it's pi; trebla is not in the habit of making such a typo.
Provided n > 0 it's all ok. So azureus88's solution stands.
 
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harism

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Don't think it's pi; trebla is not in the habit of making such a typo.
Provided n > 0 it's all ok. So azureus88's solution stands.
its not a typo, drongoski.
check it yourself... copy what looks like an 'n' and paste it into word. you will see its a pi, not an n.

i had mistaken it for an 'n' myself. But it was gurmies who knocked some sense into me.
 
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