A quick question (1 Viewer)

mc1007 · Apr 17, 2010

Find in index notation
$\frac{a}{b^3c^2}\\if \\a = \left ( \frac{2}{5} \right )^4 \\b = \left ( \frac{-1}{3} \right ) \\c = \left ( \frac{3}{5} \right )^2$

I know this is a simple case of substitution but i'm not sure how this can be expressed in index notation. Any help appreciated.

shaon0 · Apr 17, 2010

mc1007 said:
Find in index notation
$\frac{a}{b^3c^2}\\if \\a = \left ( \frac{2}{5} \right )^4 \\b = \left ( \frac{-1}{3} \right ) \\c = \left ( \frac{3}{5} \right )^2$

I know this is a simple case of substitution but i'm not sure how this can be expressed in index notation. Any help appreciated.

K=a/(b^3*c^2)
=(2/5)^4/[(-1/3)^3(3/5)^4]
=[(2/5)^4/(3/5)^4]*1/(-1/27)
=-27*[2/5/3/5]^4
=-27*[2/3]^4
=[-(3)^3/(3)^4].2^4
=-1/3.2^4
=-(2^4)/3
=-(2^4)*3^(-1)

A quick question (1 Viewer)

mc1007

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shaon0

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