Another projectile motion Q. (1 Viewer)

[Smilebuffalo]

An object is projected with horizontal velocity 8ms^-1 and vertical velocity 5ms^-1. Find the range of its flight. (use g = 10ms^-2)

 

[davidgoes4wce]

Vertical Component
ÿ=-10
ẏ=∫ -10 dt= -10t + C
t=0 y=5
C=5

ẏ=-10t + 5

y=∫-10t+5 dt
y=-5t^2+5t+C
t=0,y=0
C=0
y=-5t^2+5t
let y=0
0=-5t(t-1)
t=1

Horizontal Components
ẍ=0
ẋ=∫ 0 dt= 0t +C
when t=0, ẋ=8

ẋ=8

x=∫8 dt
when t=0, x=0
x=8t+ C
C=0

x=8t

let t=1

x=8*1=8 metres

 

[madanu]

what happened to the sin

 

[KloppsAndRobbers]

what happened to the sin

There's no need for sin or cos because the velocities are already given.