Saturn WY15
Member
- Joined
- May 21, 2010
- Messages
- 129
- Gender
- Male
- HSC
- 2012
So basically can we use L'Hospital's Rule for lim question (lim x>0 sinx/x) etc
+1.Also, L'hopital's rule isn't in the syllabus so maybe avoid it.
if you can't use an alternate method in school what makes you think you'll be able to for HSC?I'd avoid it. I use it in school exams but for externals I'm not going to.
Probably not. Otherwise it'd be in the syllabus.So basically can we use L'Hospital's Rule for lim question (lim x>0 sinx/x) etc
I am allowed to use alternate methods in school.if you can't use an alternate method in school what makes you think you'll be able to for HSC?
In high school, it's sort of an identity that the limit of sin(x)/x = 1, and they say that due to small angle approximations. Since they treat it as an identity, you just need to manipulate similar questions to get it into the form of sin(x)/x or likewise.So basically can we use L'Hospital's Rule for lim question (lim x>0 sinx/x) etc
I think you are technically allowed to but its stupid becauseif you can't use an alternate method in school what makes you think you'll be able to for HSC?
Yeah i know but i just find it so much easier using the L'Hospital rule. Oh well ;0I think you are technically allowed to but its stupid because
a) As you and D94 have pointed out, there is an easy method in the syllabus which can be used
b) If your marker does not have the mathematical knowledge to understand the alternate methods you use, its likely they will assume you're talking out of your ass and give you minimal marks. In other words, its risky and tbh if you have the ability to comprehend and utilise out of syllabus mathematics, you should have the ability to solve those questions with the methods in the syllabus anyway
Yes because Taylor Series is part of the HSC...Another way is the taylor series expansion.
ie. sin x / x = (x-x^3/3!+x^5/5!- ....) / x = 1 - (x^2/3!-x^4/5!+...)
It is clear that if you set x->0 then sin x / x -> 1.