K Kanane Member Joined Oct 15, 2009 Messages 109 Gender Male HSC N/A Oct 2, 2011 #1 A parabola whose equation is y=ax^2 where a is a constant' has the line y=12x+3 as a tangent. By using the discriminant of the quadratic equation found, find the value of a Thanks >_<
A parabola whose equation is y=ax^2 where a is a constant' has the line y=12x+3 as a tangent. By using the discriminant of the quadratic equation found, find the value of a Thanks >_<
anne1010 Member Joined Mar 31, 2010 Messages 367 Gender Female HSC 2011 Oct 2, 2011 #2 equate the two equations. ull get a quadratic. find the discriminant and since they touch one it should equal to 0. then solve for a
equate the two equations. ull get a quadratic. find the discriminant and since they touch one it should equal to 0. then solve for a
jnney lemon Joined Mar 3, 2011 Messages 1,437 Gender Female HSC 2012 Oct 2, 2011 #3 ax^2 = 12x + 3 ax^2 - 12x - 3 = 0 delta = 144 + 12a delta = 0 for tangent 144 = -12a a = -12
K Kanane Member Joined Oct 15, 2009 Messages 109 Gender Male HSC N/A Oct 2, 2011 #4 Ooh much thanks to both of you haha x]
jnney lemon Joined Mar 3, 2011 Messages 1,437 Gender Female HSC 2012 Oct 2, 2011 #5 Hehe no problem. Thanks for the rep. Good luck for hsc!
