N NizDiz Member Joined Nov 5, 2011 Messages 294 Gender Male HSC 2013 May 26, 2013 #1 Just started doing revision for upcoming trials. How would you approach 3 Thanks Attachments IMG_20130526_0001.pdf 660.1 KB Views: 138
nightweaver066 Well-Known Member Joined Jul 7, 2010 Messages 1,585 Gender Male HSC 2012 May 26, 2013 #2 Since BaNO3 is added in excess, all the sulfate ions have combined with Ba2+ ions to form BaSO4. Find the number of moles of BaSO4. Now, n(BaSO4):n(SO4 2-) = 1:1 so now you know the number of moles of SO4 2-. [SO4 2-] = n(SO4 2-)/V = n(SO4 2-)/(0.2) to get your answer.
Since BaNO3 is added in excess, all the sulfate ions have combined with Ba2+ ions to form BaSO4. Find the number of moles of BaSO4. Now, n(BaSO4):n(SO4 2-) = 1:1 so now you know the number of moles of SO4 2-. [SO4 2-] = n(SO4 2-)/V = n(SO4 2-)/(0.2) to get your answer.
N NizDiz Member Joined Nov 5, 2011 Messages 294 Gender Male HSC 2013 May 27, 2013 #3 where did the 0.2 at the end come from?
C Chubbeh Member Joined Mar 24, 2012 Messages 59 Gender Male HSC 2013 May 27, 2013 #4 NizDiz said: where did the 0.2 at the end come from? Click to expand... Volume = 200mL = 0.2L (first thing written) in the question
NizDiz said: where did the 0.2 at the end come from? Click to expand... Volume = 200mL = 0.2L (first thing written) in the question
N nerdasdasd Dont.msg.me.about.english Joined Jul 29, 2009 Messages 5,353 Location A, A Gender Male HSC 2012 Uni Grad 2017 May 27, 2013 #5 Chubbeh said: Volume = 200mL = 0.2L (first thing written) in the question Click to expand... The volume is always expressed as litres.
Chubbeh said: Volume = 200mL = 0.2L (first thing written) in the question Click to expand... The volume is always expressed as litres.
N NizDiz Member Joined Nov 5, 2011 Messages 294 Gender Male HSC 2013 May 27, 2013 #6 yeh silly me, my bad ahah, thanks for the help champion!!!