Binomial Question (1 Viewer)

[RofL]

This is from HSC 2004, q7 Show that for all positiver integers n, x[ (1+x)^n-1 + (1+x)^n-2 +...+ (1+x)^2 + (1+x) + 1 ] = (1+x)^n-1 ii) Hence show that for 1< and= k < and= n, (n-1) + (n-2) + ... + (k-1) = (n) (k-1) (k-1) (k-1) (k) ( ) ( ) is nCr (the combinations thing) I can't do the second part. Help pls EDIT: ok, doesn't format properly. So yea, if someone has ext 1 2004 q7b, can someone explain part 2??

 

[youngminii]

< br > without the spaces is line break Fix up the post and people will consider answering

 

[kwabon]

This is from HSC 2004, q7 Show that for all positiver integers n, x[ (1+x)^n-1 + (1+x)^n-2 +...+ (1+x)^2 + (1+x) + 1 ] = (1+x)^n-1 ii) Hence show that for 1< and= k < and= n, (n-1) + (n-2) + ... + (k-1) = (n) (k-1) (k-1) (k-1) (k) ( ) ( ) is nCr (the combinations thing) I can't do the second part. Help pls EDIT: ok, doesn't format properly. So yea, if someone has ext 1 2004 q7b, can someone explain part 2??

i wouldnt worry about that question if i were you. its a ridiculous question, they will never ask that every again. and for me to explain, i will prolly need about an hour, but with 4 unit in the way, nnnaaaaahhhh fuck that.

 

[RofL]

< br > without the spaces is line break Fix up the post and people will consider answering

BOS is not working for me atm... i have no gui (i think thats what its called)

 

[youngminii]

As in type < br > without the spaces, you gronk