Bored of Studies Trial Discussion Thread. (2 Viewers)

[HeroicPandas]

WOW!!! THIS EXAM is CRAZY O__O
WOW great job Carrotsticks!

 

[Timske]

apt = 90 -> bpt = 90
aqt = 90 -> cqt = 90

therefore BC subtends equal angles at two distinct points P and Q

im assuming its 12 i) i let angle APQ = x , angle ATQ = x , APQ = ATQ = x (angles subtended by same arc are equal)

angle AQT = 90 (angle in semi circle)
therefore angle TQC = 90 , (angle sum of st line)
angle QTC = 180 - (90 + x) = 90 - x (angle sum of st line)
therefore angle QCT = 180 - 90 -(90-x) = x (angle sum of /\ )
angle APQ = angle QCT

 

[manscux]

Surely HSC is not going to be this hard.. is it ????? can anyone reassure me... because this exam was crazyyy.... chalenging... and harder than any thing i have seen before


i thought my teachers exams were hard and she wrote the 4unit text book..... but carrot sticks just took it to a new level...

 

[Solution]

Surely HSC is not going to be this hard.. is it ????? can anyone reassure me... because this exam was crazyyy.... chalenging... and harder than any thing i have seen before


i thought my teachers exams were hard and she wrote the 4unit text book..... but carrot sticks just took it to a new level...

No it will not get this hard. This is the upper end of 3u maths I think ie Pretty advanced and much harder than your standard hsc paper

 

[chriss95]

im assuming its 12 i) i let angle APQ = x , angle ATQ = x , APQ = ATQ = x (angles subtended by same arc are equal)

angle AQT = 90 (angle in semi circle)
therefore angle TQC = 90 , (angle sum of st line)
angle QTC = 180 - (90 + x) = 90 - x (angle sum of st line)
therefore angle QCT = 180 - 90 -(90-x) = x (angle sum of /\ )
angle APQ = angle QCT

I think my method was much easier; although it doesn't often pop up like that in MX1, more in MX2, because it's a bit more abstract.

 

[Timske]

I think my method was much easier; although it doesn't often pop up like that in MX1, more in MX2, because it's a bit more abstract.

How did u do q13 the acceleration q

 

[gr_111]

Howz them marks coming along Carrot? not worth marking mine but i'm still curious!

 

[Carrotsticks]

Haven't marked properly yet. Will do so once this test is finished.

Best place to mark is at a cafe, drinking coffee + eating a sandwich.

 

[Carrotsticks]

Haven't marked properly yet. Will do so once this test is finished.

Best place to mark is at a cafe, drinking coffee + eating a sandwich.

 

[gr_111]

Haven't marked properly yet. Will do so once this test is finished.

Best place to mark is at a cafe, drinking coffee + eating a sandwich.

lol righto!

 

[chriss95]

Really the only one I missed up until q14. Didn't do the best in the last question though

 

[Amleops]

Very nice exam. Based on a superficial reading it's definitely the most challenging exam I've seen so far. Kudos to you Carrot.

Shall work on it tomorrow morning.

 

[Sanjeet]

How are results getting back?

 

[Carrotsticks]

I will PM the individual user.

 

[sick_kent]

quite possibly the hardest maths test i have seen,
am hoping I at least get some marks on the board, but I'm not confident :/
how is everyone's study going now?
and when do you think we will get our marks back carrotsticks?

 

[HeroicPandas]

Hey can someone please post up their solution for Q12 a)b)i)ii)d)i)ii) ans q13 d)all thanks please again!

My brain is out of energy and i can never do those questions

 

[lgnorance]

add Bcos^2(nt/2) and subtract it and then it cancels to the form x=(A-B)cos(nt)+B, you didn't have to differentiate. and from there ii) followed, through subbing in values.

can you please explain why you don't need to differentiate from here? i'm fairly sure that to prove something is simple harmonic, you need to prove and show it in the from a = -n^2*x
and when you differentiate that twice, (or when i do it rather), i'm left with:

(-n^2 / 4 )* (A-B + x)

clearly, this isn't the form. someone help please or post up their solution :/

 

[barbernator]

can you please explain why you don't need to differentiate from here? i'm fairly sure that to prove something is simple harmonic, you need to prove and show it in the from a = -n^2*x
and when you differentiate that twice, (or when i do it rather), i'm left with:

(-n^2 / 4 )* (A-B + x)

clearly, this isn't the form. someone help please or post up their solution :/

A particle can also be said to be in simple harmonic motion if it is in the form x = acos(nt+e) or asin(nt+e). So by manipulating the equation algebraically you can get it into that form and then you can say hence the particle is in simple harmonic motion.

 

[Carrotsticks]

Marking is complete and I will be sending results individually, and gradually, over the rest of today.

Solutions will be out in a few days time. If you have any question at the moment, please feel free to PM myself.

 

[deswa1]

Oooh shit haha- my mark will be interesting

Thanks SO much though for doing this