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Calculus question (1 Viewer)

suclid003

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Is it possible to integrate e^(x^2)? I've tried integration by parts and it doesn't work. Is there another technique I have to use? If only there were an x in front...
 

JhK89

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umm i think it is...
im not if its right

never tried

(x^3)/3 * e^(x^2)...?

i just intergrated the power....o_O
 

acmilan

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umm its possible, but i dont think with any methods learnt in the hsc. You'll have to start integrating polar coordinates and use double integration
 

fishy89sg

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wouldnt the x still be there if you differentiated 1/2x*e^(x^2)??

and wheres everyones +C? :)
 
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pLuvia

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No, he meant to type: 1/(2x)*ex2, but that is not the right answer either way
 

shazeh

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it cant be integrated. however we can use tarpezium law ( it gives inaccurate answer) learnt in alevels.
 

Anonymou5

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Just finding an antiderivative? You can't do it in terms of 'elementary functions.' Polar coordinates is only helpful if you want to evaluate a definite integral over an infinite or semi-infinite interval.

Edit: Sorry, I meant semi-infinite interval. I've fixed it up now.
 
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katykins

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SoulSearcher said:
Doesn't work out. You can see if you try to derive the answer you have just got.
woah wowee i just tried and i got:

(-2/x^2 * e^(x^2)) + e^(x^2)


it seems like such a simple question, you know like ive been asked it before.. but wow it really doesnt work.

im going to show my teacher tomorrow... we'll see what kooky solution she comes up with!
 

acmilan

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katykins said:
woah wowee i just tried and i got:

(-2/x^2 * e^(x^2)) + e^(x^2)


it seems like such a simple question, you know like ive been asked it before.. but wow it really doesnt work.

im going to show my teacher tomorrow... we'll see what kooky solution she comes up with!
She wont be able to answer it, it's well known you cant solve it using standard methods
 

Riviet

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katykins said:
im going to show my teacher tomorrow... we'll see what kooky solution she comes up with!
Well if she does come up with a solution, she'll probably just tell you that it's not within the scope of the HSC course. ;):p
 

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