CurdleRocket26
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- Jan 10, 2021
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- 2024
Here u go
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Im also not sure why you are multiplying by two in the final answer? And where does the go?remember it's not
Is that right broHere u go
Ok just divide it by log 3/2Im also not sure why you are multiplying by two in the final answer? And where does the go?
I would suggest revising logarithms as a whole.Is that right bro
What did i do wrongI would suggest revising logarithms as a whole.
I was talking about this oneHere u go
is not equivalent to ?What did i do wrong
Oh I haven’t learnt this yetNot quite, good attempt though. Remember how to convert an expression in exponential form to a logarithm.
i.e, Recall back to this relationship: View attachment 29933
No log xe = log 5is not equivalent to ?
Thats one of the definitions of the log function usually your meant to learn that at the start...Oh I haven’t learnt this yet
I have only learnt the log laws not the functionsThats one of the definitions of the log function usually your meant to learn that at the start...
Even then that isnt equivalent... (and you didn't write that in your working)No log xe = log 5
Ok prove the log laws?I have only learnt the log laws not the functions
Wait should i learn the log functionsEven then that isnt equivalent... (and you didn't write that in your working)
In that case, I suggest you touch up more on how logarithms work. Trust me, you will need to know them when you learn calculus in Stage 6.Oh I haven’t learnt this yet
E to the power of x =5 you have to take log base 10 of both sides then xlog10 e =log 5 then you divide log 5/log 10Wait should i learn the log functions
^ Try this next. You said you have learnt it.Ok prove the log laws?
Oh ye i have just started learning higher level of maths bc I’m only in Y8In that case, I suggest you touch up more on how logarithms work. Trust me, you will need to know them when you learn calculus in Stage 6.