I got a geometry question that looks deviously simple but alas I have not had any success.
Q8 Circle Geometry in 1998 4U past paper
AB is diamater of a circle. A chord RQ is drawn intersecting AB at 45 degrees at P.
Prove AB^2 = 2(PQ^2+PR^2)
Diagram attached.
Q8 Circle Geometry in 1998 4U past paper
AB is diamater of a circle. A chord RQ is drawn intersecting AB at 45 degrees at P.
Prove AB^2 = 2(PQ^2+PR^2)
Diagram attached.