circuit q pls help yr 11 (1 Viewer)

[yashbb]

pt b how do i do

 

[Vaibhav123456]

I dont remember circuits too well but i believe you minus the voltage drop from the first resistor. So V = 15 - 4 = 11V. Then you use this voltage for the second resistor and the current from part a.

 

[yashbb]

I dont remember circuits too well but i believe you minus the voltage drop from the first resistor. So V = 15 - 4 = 11V. Then you use this voltage for the second resistor and the current from part a.

thank you so so much you are correct.

 

[notme123]

Don't worry too much about circuits if you're stuck because it doesn't come back in detail in year 12. I personally sucked at this and was happy to not see it return.

 

[yashbb]

Don't worry too much about circuits if you're stuck because it doesn't come back in detail in year 12. I personally sucked at this as was happy to not see it return.

ok ok ok tysm, does magnetism come back?

 

[dasfas]

Yeah what Vaibhav said

Voltage across the 5Ω resistor is 4V, hence the current i = 4/5A. Since the resistors are in series, you know the current through R is 4/5A. We can use KVL to determine that the voltage is 11V across R, hence re-arranging R = V/i, we get an expression for the unknown resistor R.

 

[notme123]

ok ok ok tysm, does magnetism come back?

Yes it does and theres more depth to it but you dont have to know thoery like ferromagnetic materials and bs like that.