• Congratulations to the Class of 2024 on your results!
    Let us know how you went here
    Got a question about your uni preferences? Ask us here

Complex Number Question Urgent (1 Viewer)

theprodigy

New Member
Joined
Sep 11, 2008
Messages
16
Gender
Male
HSC
2009
far out.. this questions got me wrappedround.. and i think its really simple too


If Z is a complex number such that Z + 1/z is real, prove that either Im(z) = 0 or |z| =1
 

jules.09

Member
Joined
Jun 23, 2007
Messages
360
Gender
Undisclosed
HSC
2009
Make z = x+iy

Then sub into z + 1/z.

Then multiply 1/(x+iy) by its conjugate (x-iy).

Then split into real and imaginary parts. It's been stated that it's real? So you make the imaginary part = 0.

i.e. (x+iy) + (x-iy)/(x^2 + y^2)

x/(x^2 + y^2) + x + i[y - y/(x^2 + y^2)]

y - y/(x^2 + y^2) = 0.

Which means that x^2 + y^2 = 1. When you get the square root of both sides, you end up with |z| = 1.
 

cutemouse

Account Closed
Joined
Apr 23, 2007
Messages
2,250
Gender
Undisclosed
HSC
N/A
Notice that there's a capital 'Z', which is different from lower case 'z'.

So I don't think your answer is correct.
 

alakazimmy

Member
Joined
May 6, 2006
Messages
71
Gender
Male
HSC
2007
theprodigy said:
far out.. this questions got me wrappedround.. and i think its really simple too


If Z is a complex number such that Z + 1/z is real, prove that either Im(z) = 0 or |z| =1
Okay, we have Z is complex, Z + 1/z is real.

That means Im(Z + 1/z) = 0

The imaginary part of a complex number, say x, is (x-conjugate(x))/2i
For x = a + bi.
x - conjugate(x) = a + bi - (a - bi) = 2bi, and 2bi/2i = b, which is the imaginary part of x.
Apply this, by letting x = Z + 1/z

So Im(Z + 1/z) = ((Z + 1/z) - conjugate(Z + 1/z))/2i = 0. (We can ignore the denominator of 2i)
(Z + 1/z) - conjugate(Z) - conjugate(1/z) = 0
(Z - conjugate (Z)) - (1/z - conjuagte(1/z)) = 0
2i*Im(Z) - (2i*Im(z)/|z|2)=0

This question has infinite solutions, as they are 2 variables, and only one equation restricting them. I think both the z's are the same case.

Here's a scenario which contradicts the question.
Assume Im(z) =0. Then 1/z is obviously real. But Z is complex. Hence Z+1/z cannot be real.
Assume |z|=1, 1/z = conjugate(z)/|z|2 = conjugate(z), which is complex.
 
Last edited:

alakazimmy

Member
Joined
May 6, 2006
Messages
71
Gender
Male
HSC
2007
Okay, for both z's the same case, the question seems to be correct.

Im(x) = (x - conjugate(x))/2i

Im(z + 1/z) = 0
So, ((z + 1/z) - conjugate(z + 1/z))=0
(z - conjugate(z)) + (1/z - conjugate(1/z))=0
2i*Im(z) + (conjugate(z) - z)/|z|2 = 0
2i*Im(z) - 2i*Im(z)/|z|2 = 0
2i*Im(z)*(1 - 1/|z|2) = 0

Either Im(z) = 0, or (1 - 1/|z|2)
Therefore, Im(z) = 0, or |z|=1

Done :)
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top