acullen Povo postgrad Joined Aug 28, 2004 Messages 180 Location Sutherland, Sydney Gender Male HSC 2004 Feb 12, 2006 #3 Simply put, when graphing complex functions on the cartesian plane: x = Re(z) y = Im(z) and argument (equiv. to gradient) = arctan(Im(z)/Re(z))
Simply put, when graphing complex functions on the cartesian plane: x = Re(z) y = Im(z) and argument (equiv. to gradient) = arctan(Im(z)/Re(z))
R Riviet . Joined Oct 11, 2005 Messages 5,593 Gender Undisclosed HSC N/A Feb 12, 2006 #4 If asked to give a geometrical description, all you need to say is the locus of z is a horizontal line, parallel to the x-axis and 4 units above it. Last edited: Feb 12, 2006
If asked to give a geometrical description, all you need to say is the locus of z is a horizontal line, parallel to the x-axis and 4 units above it.
Trev stix Joined Jun 28, 2004 Messages 2,037 Location Pine Palace, St. Lucia, Brisbane. Gender Male HSC 2005 Feb 12, 2006 #5 Riviet said: If asked to give a geometrical description, all you need to say is the locus of z is a horizontal line, parallel to the x-axis and 4 units from it. Click to expand... 4 units <u>above</u> it.
Riviet said: If asked to give a geometrical description, all you need to say is the locus of z is a horizontal line, parallel to the x-axis and 4 units from it. Click to expand... 4 units <u>above</u> it.
R Riviet . Joined Oct 11, 2005 Messages 5,593 Gender Undisclosed HSC N/A Feb 12, 2006 #6 Yeah, forgot to say that, thanks. =)