"Complex Roots always come in pairs" (1 Viewer)

[ProdigyInspired]

I'm doing a question where

(2-i)z² - (1+i)z + 1 = 0

One of the roots is i,

therefore the other one should be the conjugate of i -> -i, isn't it?

But putting in -i doesn't give me 0.

I check Wolfram Alpha and it is an entirely separate number, how do I solve this?

 

[AlarmBell]

 

[Shadowdude]

^ yeah that

 

[braintic]

I'm doing a question where

(2-i)z² - (1+i)z + 1 = 0

One of the roots is i,

therefore the other one should be the conjugate of i -> -i, isn't it?

But putting in -i doesn't give me 0.

I check Wolfram Alpha and it is an entirely separate number, how do I solve this?

Once you see that one of the roots is i, it is much easier to use sum or product of roots than to use the quadratic formula.