Conjugate Acid/Base pair (1 Viewer)

[BlueGas]

The answer for this question is D, but can't it be A also? Aren't they both the same thing?

 

[Recondit]

Maybe the choices had to be listed repsectively as (acid/conjugate acid) and (conjugate base/base) as the the question says? That would make D the answer and not A

 

[InteGrand]

The answer for this question is D, but can't it be A also? Aren't they both the same thing?

I think by the question and answers' wording (and judging by your comment that D is the answer), they're listing the acid first in the answers (otherwise, (A) and (D) would be identical).

So for example, option (A) says that OH^– is the acid (because it was the first one listed in its pair), which is false.

 

[BlueGas]

I think by the question and answers' wording (and judging by your comment that D is the answer), they're listing the acid first in the answers (otherwise, (A) and (D) would be identical).

So for example, option (A) says that OH^– is the acid (because it was the first one listed in its pair), which is false.

Yeah I get it now, because for A, if CO3 is the acid HCO3 wouldn't because it's conjugate base because a conjugate base is the original acid but with a proton removed.

 

[someth1ng]

I think by the question and answers' wording (and judging by your comment that D is the answer), they're listing the acid first in the answers (otherwise, (A) and (D) would be identical).

So for example, option (A) says that OH^– is the acid (because it was the first one listed in its pair), which is false.

I agree with what you're saying but I think it's a pretty stupid way of making a question - it's too ambiguous and they really should be using a table for something like this.

 

[MaccaFacta]

The Bronsted-Lowry definitions for this type of equilibrium say that an acid + base <> conjugate acid + conjugate base. So, in the equation as it is written, H2O is the acid, CO3 2- is the base, HCO3 - is the conjugate acid and OH- is the conjugate base. Speaking as a teacher, I won't be copying and pasting this question into the bank of questions I have on this topic.