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Curve sketching question (1 Viewer)

trapizi

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So I just finished my 4U trial today and my teacher put a question about graphing the derivative y=f'(x) of the given function y=f(x) :eek:. The function look like this:

Can anybody show me how the derivative graph of this function look like? Thanks!!!:)
 

photastic

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I got a question, would can you approach it the same as 2u, like SP becomes roots, POI becomes SP and HPOI becomes both root and SP?
 

gahyunkk

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Is it something like this?
Someone Correct me if im wrong
ImageUploadedByTapatalk1406807086.146334.jpg

Ive got my 4u trial tmr and i feel like im so screwed :(((((
 

rumbleroar

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where there are turning points on f(x), an x-int will exist on f'(x). for triple roots, a double root will exist on f'(x)?
 

emilios

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Really? They put a simple year 11 2 unit question in the Ext 2 paper?
... graphing derivative functions when you're not given an equation is a perfectly standard 4U type question. It can be a lot trickier than some of the other stuff they test in the Graphs topic.
 

panda15

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... graphing derivative functions when you're not given an equation is a perfectly standard 4U type question. It can be a lot trickier than some of the other stuff they test in the Graphs topic.
I've never seen one in a 4U paper, but I have seen it in a 2U paper. It would be VERY easy marks in a 4U paper.
 

braintic

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... graphing derivative functions when you're not given an equation is a perfectly standard 4U type question. It can be a lot trickier than some of the other stuff they test in the Graphs topic.
No asymptotes - that is a 2 unit standard question. A 4 unit student should not have any difficulty with that one.
 

photastic

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No asymptotes - that is a 2 unit standard question. A 4 unit student should not have any difficulty with that one.
Perhaps a better 4 unit question is find the log of its reciprocal.
 

braintic

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Perhaps a better 4 unit question is find the log of its reciprocal.
I guess that would test how many people spot the quick way.

But yes, any composite function question would be harder than this.
 

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