Differentiate 9x-8/ 2(sqrt(3x-4)) (1 Viewer)

bibi34 · Mar 16, 2013

Please help?

bibi34 · Mar 16, 2013

When you differentiate (3x-4)^1/2)
Shouldn't the answer be 3/2(sqrt (3x-4))?

AAEldar · Mar 16, 2013

Come at me said:
View attachment 27830

This is not right...

$v=(3x-4)^{\frac{-1}{2}}$

kat- · Mar 16, 2013

Come at me said:
View attachment 27830

AAEldar said:
This is not right...

$v=(3x-4)^{\frac{-1}{2}}$

I think he differentiated v incorrectly as well. He forgot to times it by the derivative inside of the bracket so it should be -3/2 blah

bibi34 · Mar 16, 2013

Anybody?? Help please...

yasminee96 · Mar 17, 2013

Probably could've cut out some steps..