Differentiate question. (1 Viewer)

[monesh]

Hey guys i'm stuck on one question would really appreciate if you show working out.

Differentiate with respect to x:

i) y = 5x-3/ x^2

answer is 6-5x/x^3

thanks alot in advance

 

[Aplus]

Differentiate with respect to x:

i) y = 5x-3/ x²
dy/dx = [(x²)(5) - (2x)(5x-3)]/x⁴
= (5x² - 10x² + 6x)/x⁴
= (-5x² + 6x)/x⁴
= [x(-5x + 6)]/x⁴
= (6 - 5x)/x³

 

[Xcelz]

Answer.

5x-3/x^2

using quotient rule (vu'-uv')/v^2

=(x^2).5 - (5x-3).2x/ x^4 (dot indicates multiply)

=5x^2-10x^2+6x/ x^4 (expanded brackets)

=6x-5x^2/x^4 (rearranged)

=6-5x/x^3 (divided everything by x as it is a common factor)

Hope that helped.

 

[monesh]

cheers mate