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Domain and asymptotes (1 Viewer)

atar90plus

01000101=YES! YES! YES!
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Hello
Could someone please provide me with the solution as to finding the domain, vertical and horizontal asymptotes of the equation
y= e^x-e^-x all over (fraction) e^x+e^-x

Thanks
 

Sy123

This too shall pass
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For Vertical Asymptotes:

Find x for which



Therefore no vertical asymptotes. This might not be the only case however, in these cases, always look for certain function types that somehow restrict x in some way. But generally the denominator=0 is the way to find the ver.asymptote.

For horizontal asymptotes, since we dont have any vertical asymptotes, we only need to test for positive infinity and negative infinity. When you do that, you will notice asymptotes at y=1 and y=-1.

Domain is all real x since there is no function of x which restricts its domain (unlike for example sqrt(x) which restricts x to above 0).

So in the end, generally, once you get the vertical asymptotes (if there are any), then test positive and negative infinity, and points close to ver. asymptotes, and see if they go near an asymptote or such.

But remember, if the function is y=f(x)/g(x) where f(x) and g(x) are both polynomials, and the degree of f(x) is higher than the degree of g(x), then you have to use polynomial division, to find a possible oblique asymptote (I dont think they have asked that in the HSC though)
 

Fus Ro Dah

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Hyperbolic tangent function.

Domain: All real x.
Range: Plus/minus 1.
 
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I think in 3u they're only vertical/horizontal asymptotes..and 4u there's oblique. correct if wrong
 

Timske

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Theres oblique in 3u as well
 

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