Easy 4u, not 4me (1 Viewer)

[ekoolish]

Differentiate using the most appropriate method.
xsqrd+x+1/2sqrootx

ty

 

[Just.Snaz]

Differentiate using the most appropriate method.
xsqrd+x+1/2sqrootx

ty

i see no 'appropriate method'. I see, splitting the fraction. so it'd be x^2 / 2rootx + x/2rootx + 1/2rootx and then 2 unit integration from there.

Also, you don't have to put "easy 4u, not 4me". We won't bite/attack you if you can't do an 'easy' question

EDIT: is that [x^2 + x + 1]/2rootx ? or x^2 + x + (1/2rootx) ?

 

[ekoolish]

i see no 'appropriate method'. I see, splitting the fraction. so it'd be x^2 / 2rootx + x/2rootx + 1/2rootx and then 2 unit integration from there.

Also, you don't have to put "easy 4u, not 4me". We won't bite/attack you if you can't do an 'easy' question

EDIT: is that [x^2 + x + 1]/2rootx ? or x^2 + x + (1/2rootx) ?

the former

 

[ekoolish]

btw we havent learnt intergration yet so i was thinking of either the quotient,chain or product rule?

 

[Just.Snaz]

btw we havent learnt intergration yet so i was thinking of either the quotient,chain or product rule?

lol what? why, it's just normal integration. Don't over complicate, I used to do that heaps, not good. Just think simple first.

And well, after I split the fraction, x^2/root x becomes x^(3/2).. and for x/rootx , it becomes, x^(1/2) and 1/rootx = x^(-1/2). you can take the 1/2 outside and then just integrate.

 

[ekoolish]

lol what? why, it's just normal integration. Don't over complicate, I used to do that heaps, not good. Just think simple first.

And well, after I split the fraction, x^2/root x becomes x^(3/2).. and for x/rootx , it becomes, x^(1/2) and 1/rootx = x^(-1/2). you can take the 1/2 outside and then just integrate.

*sigh* We haven't learnt intergration...

anyone?

 

[Just.Snaz]

*sigh* We haven't learnt intergration...

anyone?

ohhhh. terribly sorry. took 4u as 4 unit. You learn integration in 4 unit as well.

I don't know how you could use either rule. just. the rule for integration is x^n becomes x^(n+1) / n+1

so x^(3/2) becomes x^(5/2) / (5/2) = 2x^(5/2) / 5

and then apply to the rest? add 1 to the power and then divide by the new power.

 

[Trebla]

ohhhh. terribly sorry. took 4u as 4 unit. You learn integration in 4 unit as well.

I don't know how you could use either rule. just. the rule for integration is x^n becomes x^(n+1) / n+1

so x^(3/2) becomes x^(5/2) / (5/2) = 2x^(5/2) / 5

and then apply to the rest? add 1 to the power and then divide by the new power.

Differentiate using the most appropriate method.
xsqrd+x+1/2sqrootx

ty

This is a DIFFERENTIATION QUESTION!!!! ROFL!!!

 

[Just.Snaz]

Oh my god, SO SORRY.

I don't know what's wrong with me

 

[ekoolish]

ohhhh. terribly sorry. took 4u as 4 unit. You learn integration in 4 unit as well.

I don't know how you could use either rule. just. the rule for integration is x^n becomes x^(n+1) / n+1

so x^(3/2) becomes x^(5/2) / (5/2) = 2x^(5/2) / 5

and then apply to the rest? add 1 to the power and then divide by the new power.

lol' k. I figured it out using the quotient rule. I hate maths

 

[bored of sc]

Differentiate using the most appropriate method.
xsqrd+x+1/2sqrootx

ty

Quotient rule?

y = [x²+x+1] / [2sqrt(x)]
dy/dx = [2x^1/2*(2x+1) - x^-1/2*(x²+x+1)] / [2x^1/2]²

The rest is an exercise in algebra.

 

[shaon0]

Differentiate using the most appropriate method.
xsqrd+x+1/2sqrootx

ty

lol

 

[gurmies]

1/2 (x^(3/2) + x^(1/2) + x^(-1/2)

dy/dx = 1/2 (3/2(x^(1/2)) + 1/(2x^(1/2)) - 1/(2x^(3/2)))

= (3rootx)/4 + 1/(4rootx) - 1/(4xrootx)

= (3x^2 + x - 1)/(4xrootx)

= (3x^2rootx + xrootx - rootx)/4x^2