Easy Question... Help Needed urgent (1 Viewer)

[SxC]

The star canopus has an aparent magnitude of -0.72 and an absolute magnitude of -3.1

(a) How far away is Canopus in parsecs?

m-M = 5log(d/10)

-0.72-(-3.1) = 5log(d/10)

5log(d/10) = 2.38

then it says (d/10) = 2.99 how did they get that???? i know its a stupid question but can anyone help me urgentlyyy plzzz

 

[helper]

log(d/10)=0.476
d/10=inv log (0.476)

 

[SxC]

inv log (0.476)?

bro i dont get that bit and the answwer says d=29.9 parsecs

 

[DavidB]

wtf????

is this supposed to be in the "ideas to implementation" forum?!?

 

[SxC]

OOOOpppps loll

sorii man wrong one hahaha

 

[helper]

Do you understand down to where I type inv log?
To inverse log, hit the inverse key then the log key. The answer should be 2.99

 

[Tredanse]

Do you understand down to where I type inv log?
To inverse log, hit the inverse key then the log key. The answer should be 2.99

Just as an addendum: on some calculators it's shift+log.

Or if you still don't understand, to get inverse log of say, "a", just type 10^a .. the ^ button sometimes looks like an x with a superscript y.

 

[Nose_Enterprise]

please sir, use "log₁₀" or "lg" for this denotes logarithm of base ten, whereas log denotes logarithm base e, and it is evidently not that.