Explanation for Calculus question needed (1 Viewer)

[jessnguyen3]

The acceleration a ms^-2 of a particle P moving in a straight line is given by a = 3(1-x^2) , where x metres is the displacement of the particle to the right of the origin. Initially the particle is at the origin moving with a velocity of 4ms^-1. Show that the velocity vms^-1 of the particle is given by v^2 = 16+6x-2x^3.

 

[integral95]

You need to use the concept



From there you integrate with respect to x then find the constant with the initial condition then multiply both sides by 2.

 

[HeroWise]