Exponential and Log Function Question Help (1 Viewer)

alussovsky · Feb 5, 2019

Hi! There's a question I've been quite confused about in the Fitzpatrick textbook:
"Calculate the area bounded by $y=e^x$ , the coordinate axes and the textbook at $x=2$ "

The working out I did:
$Area = \int_{0}^{2} (e^x-e^2(x-1)) dx$
$=[e^x-\frac{1}{2}x^2e^2+xe^2]2/0$
$=e^2-1$

I shortened some of the working, but that was what I got. The answer to that question, however, is $\frac{1}{2}e^2-1$

integral95 · Feb 5, 2019

I think you mean $\frac{1}{2}(e^2-1)$

Also I'm not sure how you got that integral cause the integral is suppose to be simply

$\int_0^2 e^x \ \ dx$

alussovsky · Feb 5, 2019

Oof, sorry, I think I got volume and area mixed up at that point, and squared y (I dunno how that mix-up happened either, lol). Anyway, it's all good now. Thanks!

Exponential and Log Function Question Help (1 Viewer)

alussovsky

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integral95

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alussovsky

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