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Extension One Revising Game (1 Viewer)

shaon0

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New question:

Let x= sec@, dx=sec@tan@ d@
I
= S (sec@tan@/(sec@sqrt((sec@)^2-1))) d@
= S d@
= @ + C
= arccos(1/x) +C

For I with limits x=3,2.
I = arccos(1/3)-arccos(1/2)
Let a=arccos(1/3), b=arccos(1/2)
I = a-b
cos(I) = cos(a-b)
cos(I) = cos(a)cos(b)+sin(a)sin(b)
cos(I) = (1/3)(1/2)+(sqrt(8)/3)(sqrt(3)/2)
cos(I) = (1/6)+sqrt(24)/6
I = arccos((1+2sqrt(6)/6)

Someone can ask a question on my behalf.
 
Last edited:

kurt.physics

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As no one has been able to solve Trebla problem, then (if you dont mind Trebla), for the sake of furthering the progress of this thread, i will post a new question.

given where and

if:



then find the value of
 
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