factorising negative quadratics (1 Viewer)

[kr73114]

i have forgotten how to do this simple question, please help.

-x^2+3x+4=0

 

[hscishard]

-(x^2-3x-4)
-(x-4)(x+1)
(4-x)(x+1)

 

[SeCKSiiMiNh]

i have forgotten how to do this simple question, please help.

-x^2+3x+4=0

use the cross product method.

(-x +4) (x +1) = 0

 

[adomad]

i have forgotten how to do this simple question, please help.

-x^2+3x+4=0

you can times both side by -1 first, to get rid of the negative sign infront of the x^2 term..

so you get X^2 -3x-4=0

by inspection... or using the quadratic formula on ur calculator, the factors are 4 and -1 hence (x-4)(x+1)=0

or use the cross method as mentioned above

X -4

X 1
________
-3X

hence the factors are (x-4)(x+1)=0