• Best of luck to the class of 2024 for their HSC exams. You got this!
    Let us know your thoughts on the HSC exams here
  • YOU can help the next generation of students in the community!
    Share your trial papers and notes on our Notes & Resources page
MedVision ad

Find True Length Size (2 Viewers)

machine2035

Member
Joined
Mar 21, 2012
Messages
65
Gender
Male
HSC
N/A
Hey,

I can't seem to find anywhere how to find the true length size from a picture. I remember something to do with making it parallel to the X-X axis (a property which will make it TL in the other view).

Help please, this question can be used as an example.
 

Attachments

soloooooo

Well-Known Member
Joined
Feb 13, 2012
Messages
3,311
Gender
Female
HSC
N/A
I can't solve it based on that picture as there are no dimensions given.

It is just 3d trigonometry though.
 

machine2035

Member
Joined
Mar 21, 2012
Messages
65
Gender
Male
HSC
N/A
I can't solve it based on that picture as there are no dimensions given.

It is just 3d trigonometry though.
Can you just make up sizes so I can see how its done? I don't really care as long as I can understand it.
 

gr_111

Member
Joined
May 2, 2012
Messages
162
Gender
Male
HSC
2012
no its quite easy, you just have to project them both to the same plane.

i'm doing a pic, just wait...

as.jpg



you pivot x around until it is horizontal, then project it straight down until it intersects the horizontal line of the top of the beam. Then measure 'y', the blue line, to get the true length.
 
Last edited:

machine2035

Member
Joined
Mar 21, 2012
Messages
65
Gender
Male
HSC
N/A
no its quite easy, you just have to project them both to the same plane.

i'm doing a pic, just wait...

View attachment 26672



you pivot x around until it is horizontal, then project it straight down until it intersects the horizontal line of the top of the beam. Then measure 'y', the blue line, to get the true length.
Awesome, thanks.

I was getting the red line part but just got confused on how far you project it straight down.. I understand now
 

lemon1

Member
Joined
Dec 15, 2011
Messages
71
Gender
Female
HSC
2012
no its quite easy, you just have to project them both to the same plane.

i'm doing a pic, just wait...

View attachment 26672



you pivot x around until it is horizontal, then project it straight down until it intersects the horizontal line of the top of the beam. Then measure 'y', the blue line, to get the true length.
For some reason i'm not understanding it
 

vinhkn

Member
Joined
Apr 3, 2011
Messages
50
Gender
Male
HSC
2012
Oh so you use a compass to draw that arc from that point on the beam to when it hits the red line then project straight down. Is the blue line from that point to where it hits the projected line? :S
 

machine2035

Member
Joined
Mar 21, 2012
Messages
65
Gender
Male
HSC
N/A
Just did another one to make sure I was catching on correct.

Can someone confirm this is the correct way to do it. Yellow is the new line which is true length.. Please let me know if its right :)

TL.png
 

gr_111

Member
Joined
May 2, 2012
Messages
162
Gender
Male
HSC
2012
You can disregard the vertical line in the bottom view, because since it's vertical, it is already its true length. so just work out the angled section, then add it to the vertical section, like this:
001.jpg
 

machine2035

Member
Joined
Mar 21, 2012
Messages
65
Gender
Male
HSC
N/A
You can disregard the vertical line in the bottom view, because since it's vertical, it is already its true length. so just work out the angled section, then add it to the vertical section, like this:
View attachment 26743
Awesome.. Would my way still get the right answer.. I haven't printed it out so I am not able to measure and thence apply the scale to see what length I get.
 

gr_111

Member
Joined
May 2, 2012
Messages
162
Gender
Male
HSC
2012
I don't think your way would work, because that vertical line is only in one dimension, i.e. only has 'height', and no 'depth' or 'width', but by putting it on the other view you are saying that it does have width or depth.
 

Users Who Are Viewing This Thread (Users: 0, Guests: 2)

Top