Finding the value of pH question (1 Viewer)

[enigma_1]

Find the pH when 2.34g of sulphuric acid is added to 5L of water.

What do you guys get for this? This is the equation right?

H2SO4 ---> 2H+ + SO4 ^2-

 

[hit patel]

Find the pH when 2.34g of sulphuric acid is added to 5L of water.

What do you guys get for this? This is the equation right?

H2SO4 ---> 2H+ + SO4 ^2-

Hey,
Uh?>?? I am not completely sure but from the top of my head from what I remember from my notes:
Moles of sulfuric acid: 2.34/ (1.008 x 2 +64 + 32.065)= 2.38578 x 10^-2
Moles of H+ ions: = 2 x 2.38578 x 10^-2 = 4.771566 x 10^-2 mol
Concentration of H+ ions using c= n/v = 4.771566 x 10^-2/ 5 = 9.5431327 x 10^-3 mol/L
pH= -log(9.5431327 x 10^-3 = 2.02

Which I am not sure would be right. I think it is too acidic. Please verify. I havent even done one question relating to this topic. But from what I have understood from the textbook and using some stoichiometry I did this.

 

[enigma_1]

Thanks man! The method seems right, but yeah I agree it seems a bit too acidic. Thanks for help btw

 

[hit patel]

Thanks man! The method seems right, but yeah I agree it seems a bit too acidic. Thanks for help btw

No Problem K, Uh if I may ask what book is this from?