• Congratulations to the Class of 2024 on your results!
    Let us know how you went here
    Got a question about your uni preferences? Ask us here

Functions (1 Viewer)

lyounamu

Reborn
Joined
Oct 28, 2007
Messages
9,998
Gender
Male
HSC
N/A
Sorry, I didn't see the 'square root' thing. Yes, continuum's one is right.
 

lyounamu

Reborn
Joined
Oct 28, 2007
Messages
9,998
Gender
Male
HSC
N/A
Continuum said:
f(x) = sqrt(x^2+2x-3)
Anything inside a square root sign must be greater than or equal to zero. Hence:
x^2+2x-3 >= 0
(x+3)(x-1) >= 0
x <= 3 and x >= 1

y <=-3 by the way. Otherwise it's perfectly right. :rolleyes:
 

kurt.physics

Member
Joined
Jun 16, 2007
Messages
840
Gender
Undisclosed
HSC
N/A
on a mac it is: option + v

on a pc: i would imagine its alt + v


where i have put a plus, it means at the same time, you can hold down alt and then press v but alt must be down aswell.

 

Sew2289

Member
Joined
May 20, 2007
Messages
46
Gender
Male
HSC
2008
Hey guys can somebody kindly help me with the answer to this?

if F(x)=X^2+3x

Find in simplest form

f(x+h)-f(x)
h

I tried to figure it out, don't know if I did it right though.

Thanks.
 

lyounamu

Reborn
Joined
Oct 28, 2007
Messages
9,998
Gender
Male
HSC
N/A
Sew2289 said:
Hey guys can somebody kindly help me with the answer to this?

if F(x)=X^2+3x

Find in simplest form

f(x+h)-f(x)
h

I tried to figure it out, don't know if I did it right though.

Thanks.
Answer is 2x + h +3

EDIT: Are you doing the first principle of derivative? Then you should put the limit sign as well (if not, don't worry).

FURTHER EDITION: If you need my working out, I will post it up.
 
Last edited:

Sew2289

Member
Joined
May 20, 2007
Messages
46
Gender
Male
HSC
2008
No we havent done derrivatives yet (Im term 2 year 11, I know my profile says 2008). I didnt somehow get the h in my answer I only had 2x+3. How did you work out your answer?
 

lyounamu

Reborn
Joined
Oct 28, 2007
Messages
9,998
Gender
Male
HSC
N/A
Sew2289 said:
No we havent done derrivatives yet (Im term 2 year 11, I know my profile says 2008). I didnt somehow get the h in my answer I only had 2x+3. How did you work out your answer?
My working out is like the followings:

f(x) = x^2 +3x / h
Then f(x+h) = (x+h)^2 + 3(x+h)
= x^2 +2hx + h^2 +3x +3h

Therefore, f(x+h) - f(x) / h = x^2 +2hx+h^2 +3x +3h-(x^2 + 3x)/h
= x^2 +2hx +h^2 +3x +3h -x^2 -3x /h
= 2xh + h^2 +3h /h
= 2x + h +3
 

tommykins

i am number -e^i*pi
Joined
Feb 18, 2007
Messages
5,730
Gender
Male
HSC
2008
Turns out to be 2x + h + 3.
EDIT : let me actually do it.
 
Last edited:

lyounamu

Reborn
Joined
Oct 28, 2007
Messages
9,998
Gender
Male
HSC
N/A
tommykins said:
It should only be 2x+3, the h cancels out.

That's differentiating from first principles, there shouldn't be a h.

EDIT : let me actually do it.
I know, but he is not doing this from the first derivative. :D
 

kurt.physics

Member
Joined
Jun 16, 2007
Messages
840
Gender
Undisclosed
HSC
N/A
Sew2289 said:
Hey guys can somebody kindly help me with the answer to this?

if F(x)=X^2+3x

Find in simplest form

f(x+h)-f(x)
h

I tried to figure it out, don't know if I did it right though.

Thanks.
f(x+h) = (x+h)2 + 3(x+h)
= x2 + 2hx + h2 + 3x + 3h


f(x) = x2 + 3x

f(x+h) - f(x) = x2 + 2hx + h2 + 3x + 3h - (x2 + 3x)

= x2 + 2hx + h2 + 3x + 3h -x2 - 3x
= h2 + 2hx + 3h


f(x+h)-f(x) = (h2 + 2hx + 3h) ÷ h
h
= (h(h+2x+3)) ÷ h

= h + 2x + 3
 
Last edited:

Sew2289

Member
Joined
May 20, 2007
Messages
46
Gender
Male
HSC
2008
lyounamu said:
My working out is like the followings:

f(x) = x^2 +3x / h
Then f(x+h) = (x+h)^2 + 3(x+h)
= x^2 +2hx + h^2 +3x +3h

Therefore, f(x+h) - f(x) / h = x^2 +2hx+h^2 +3x +3h-(x^2 + 3x)/h
= x^2 +2hx +h^2 +3x +3h -x^2 -3x /h
= 2xh + h^2 +3h /h
= 2x + h +3
Cheers Mate, your like a bullet at replying, top stuff!
 

adidasboy

weee
Joined
Feb 6, 2007
Messages
336
Location
syd
Gender
Male
HSC
2009
√ oh its alt 251
Googled it lol.
looks more like a tick than square root
 

tommykins

i am number -e^i*pi
Joined
Feb 18, 2007
Messages
5,730
Gender
Male
HSC
2008
lyounamu said:
I know, but he is not doing this from the first derivative. :D
Yeah fixed it when I actually did the q. :p
 

Continuum

I'm squishy
Joined
Sep 13, 2007
Messages
1,102
Gender
Male
HSC
2009
Sew2289 said:
No we havent done derrivatives yet (Im term 2 year 11, I know my profile says 2008). I didnt somehow get the h in my answer I only had 2x+3. How did you work out your answer?
It's funny how you got the answer 2x+3, since that's the answer if you approached the question using differentiation.
 

lyounamu

Reborn
Joined
Oct 28, 2007
Messages
9,998
Gender
Male
HSC
N/A
Continuum said:
It's funny how you got the answer 2x+3, since that's the answer if you approached the question using differentiation.
May be he thought that we were using the first derivative where we have limit sign where h approaching 0. Then, we have 2x +h +3 where h becomes 0, which becomes 2x +3.
 

cherry1991

New Member
Joined
Mar 1, 2008
Messages
17
Gender
Undisclosed
HSC
2009
Functions Assignment

The scientist Galilea discovered that the period of a pendulum(the time for one complete swing) is a function of its length
a) use function notation to express this statment
i think its f(L)=t ?

b. An approximate model for the motion of a pendulum is that the period (in seconds) is twice the square root of the lenth ( in metres). Write this model as an algebraic formula
T=2 square root L ?
Calculate a few values of the function and sketch its graph
so what kinda graph? like i know i put different lengths and get different times but i duno how to sketch it
So length 4 the period of time would be: 4 seconds
length 16 the period of time would be: 8 seconds

d. if u have 2 pendulums, with the length of one four times the length of the other, how will their periods compare? Write your answer using function notationNEED HELP WITH THIS QUESTION

 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top