L letsdie45 New Member Joined May 20, 2008 Messages 23 Gender Undisclosed HSC 2010 Sep 7, 2009 #1 How would i go about sketching y = |x| ± sqrt(4-x2) ?
tommykins i am number -e^i*pi Joined Feb 18, 2007 Messages 5,730 Gender Male HSC 2008 Sep 7, 2009 #2 draw |x| then draw sqrt(4-x^2) then add 'em xD
untouchablecuz Active Member Joined Mar 25, 2008 Messages 1,693 Gender Male HSC 2009 Sep 7, 2009 #3 find the derivative of y = |x|+- sqrt(4-x^2) @ x=0
Trebla Administrator Administrator Joined Feb 16, 2005 Messages 8,401 Gender Male HSC 2006 Sep 7, 2009 #4 It graphs out to be a loveheart shape lol.....
tommykins i am number -e^i*pi Joined Feb 18, 2007 Messages 5,730 Gender Male HSC 2008 Sep 7, 2009 #5 Much more efficient than this parametric curve my uni book gives me.
T Timothy.Siu Prophet 9 Joined Aug 6, 2008 Messages 3,449 Location Sydney Gender Male HSC 2009 Sep 8, 2009 #6 Trebla said: It graphs out to be a loveheart shape lol..... Click to expand... indeed it does, how pretty.
Trebla said: It graphs out to be a loveheart shape lol..... Click to expand... indeed it does, how pretty.
addikaye03 The A-Team Joined Nov 16, 2006 Messages 1,267 Location Albury-Wodonga, NSW Gender Male HSC 2008 Sep 8, 2009 #7 Put this into Graphmatica: x^2+[(5y/4)-sqrt(|x|)]^2=1