Q2C-ME
2SUS
- Joined
- Jul 30, 2006
- Messages
- 262
- Gender
- Male
- HSC
- 2008
question 7
a)
i] Q <---theta
therefore Q/360 X 2 X pie X R
15/360 X 2pie X 6400 = 1676 (nearest Km)
ii] 8 X 1.852 = 14.816km/hr
therefore 1676 / 18.8 = 113hours
iii] 10:00am Tue 12th Dec ( 113/24= 4ish and bout 7/10 days)
therefore = 4 days = 10:00am Sat 16th Dec
= 17 hours = 0300 or 3:00am Sunday 17th Dec
a)
i] Q <---theta
therefore Q/360 X 2 X pie X R
15/360 X 2pie X 6400 = 1676 (nearest Km)
ii] 8 X 1.852 = 14.816km/hr
therefore 1676 / 18.8 = 113hours
iii] 10:00am Tue 12th Dec ( 113/24= 4ish and bout 7/10 days)
therefore = 4 days = 10:00am Sat 16th Dec
= 17 hours = 0300 or 3:00am Sunday 17th Dec