• Congratulations to the Class of 2024 on your results!
    Let us know how you went here
    Got a question about your uni preferences? Ask us here

Heeelp linear algebraaa PLS :D (1 Viewer)

hayabusaboston

Well-Known Member
Joined
Sep 26, 2011
Messages
2,387
Location
Calabi Yau Manifold
Gender
Male
HSC
2013
http://imgur.com/a/stANL

Q2 C) I am not sure what it means w-u,u,v or how to approach.

Also Q3) b,c,d I dont think my lecturer covered in any great depth and actually have no idea how to do o_O lecturer jumps so much shit.


For 3) a) I got r=(1,1,1) + s(1,0,1) + t(0,2,2), but dont know how to convert to cartesian to find if points lie on it. EDIT: Got x+2y-z=2, but now c) idk

Oh also, does not contain 0,0,0 and 0,0,2 right?
 
Last edited:

He-Mann

Vexed?
Joined
Sep 18, 2016
Messages
278
Location
Antartica
Gender
Male
HSC
N/A
Do it yourself, mate.

You're too worried about how to do these questions and whether it's something that you need to learn rather than exercising your problem solving skills.

Here I demonstrate Q3 (a), which you CAN do.

What is the structure of a cartesian equation in R3? ax+by+cz=d, where a, b, c, d are known constants. So, you need (x, y, z).

Where do you get (x, y, z) from what you have?

r = (x, y, z) = (1,1,1) + s(1,0,1) + t(0,2,2)

So, x = __, y = __, z = __.

You're nearly done but the problem here is you figure it out? Which is easily solved with your knowledge.
 

hayabusaboston

Well-Known Member
Joined
Sep 26, 2011
Messages
2,387
Location
Calabi Yau Manifold
Gender
Male
HSC
2013
Do it yourself, mate.

You're too worried about how to do these questions and whether it's something that you need to learn rather than exercising your problem solving skills.

Here I demonstrate Q3 (a), which you CAN do.

What is the structure of a cartesian equation in R3? ax+by+cz=d, where a, b, c, d are known constants. So, you need (x, y, z).

Where do you get (x, y, z) from what you have?

r = (x, y, z) = (1,1,1) + s(1,0,1) + t(0,2,2)

So, x = __, y = __, z = __.

You're nearly done but the problem here is you figure it out? Which is easily solved with your knowledge.
I got a) I just wasn't sure about b) but got that eventually now just c) and d)

also, cant see your latez for some reason
 
Last edited:

He-Mann

Vexed?
Joined
Sep 18, 2016
Messages
278
Location
Antartica
Gender
Male
HSC
N/A
There's no LaTeX present.

Hint for (c) is "what condition is required for 2 vectors to be orthogonal?" and (d) Euclid
 

He-Mann

Vexed?
Joined
Sep 18, 2016
Messages
278
Location
Antartica
Gender
Male
HSC
N/A
How are the answers ive given so far, above?
I haven't done any computations but could you explain how you got r=(1,1,1) + s(1,0,1) + t(0,2,2) because this disagrees with my understanding of planes. Sorry for the backtrack just making sure.
 

hayabusaboston

Well-Known Member
Joined
Sep 26, 2011
Messages
2,387
Location
Calabi Yau Manifold
Gender
Male
HSC
2013
I haven't done any computations but could you explain how you got r=(1,1,1) + s(1,0,1) + t(0,2,2) because this disagrees with my understanding of planes. Sorry for the backtrack just making sure.
named the points (1,1,1), (1,0,1) and (0,2,2) as PQR, did Q minus P and R minus P to find vectors u and v, denoted P(1,1,1) as ro
then from

r=r0+su+tv I plugged in results.
 

He-Mann

Vexed?
Joined
Sep 18, 2016
Messages
278
Location
Antartica
Gender
Male
HSC
N/A
named the points (1,1,1), (1,0,1) and (0,2,2) as PQR, did Q minus P and R minus P to find vectors u and v, denoted P(1,1,1) as ro
then from

r=r0+su+tv I plugged in results.
Good but r=(1,1,1) + s(1,0,1) + t(0,2,2) = r0+sQ+tR != r0+su+tv.
 

hayabusaboston

Well-Known Member
Joined
Sep 26, 2011
Messages
2,387
Location
Calabi Yau Manifold
Gender
Male
HSC
2013
Good but r=(1,1,1) + s(1,0,1) + t(0,2,2) = r0+sQ+tR != r0+su+tv.
The reason I am so broken up with my maths knowledge is because I dont revise much maths during semester I just lightly follow the lectures, I revise 2-3 weeks before the exam and thats when I start actually doing question booklets and past exams. I'm most comfortable doing that, and that gives me good results

But during the semester I will likely several times have broken knowledge and appear not to know the simplest shit for the simple reason I haven't sat down and focused on every concept in the framework i've only lightly glossed over it.

I should change this way of doing things I suppose.

Anyway is the cartesian equation x+2y-z=2, and (0,0,0) and (0,0,2) do NOT lie on the line? also for c), is the line L x-1=(y-1)/2=1-z?
 

He-Mann

Vexed?
Joined
Sep 18, 2016
Messages
278
Location
Antartica
Gender
Male
HSC
N/A
The reason I am so broken up with my maths knowledge is because I dont revise much maths during semester I just lightly follow the lectures, I revise 2-3 weeks before the exam and thats when I start actually doing question booklets and past exams. I'm most comfortable doing that, and that gives me good results

But during the semester I will likely several times have broken knowledge and appear not to know the simplest shit for the simple reason I haven't sat down and focused on every concept in the framework i've only lightly glossed over it.

I should change this way of doing things I suppose.

Anyway is the cartesian equation x+2y-z=2, and (0,0,0) and (0,0,2) do NOT lie on the line? also for c), is the line L x-1=(y-1)/2=1-z?
So you found a strategy that yields impressive grades but has an immense drawback that you know will kill you in the future as mathematics is like building a tower, you can't go far with a weak foundation. I believe the problem with your strategy is that you believe too strongly of grades. It's not an effective measurement of how well you understand the course.

I've seen a lot of students in mathematics cram just to get good grades (HD) and falsely thinking they are somewhat of an expert at this course but they are no-where as good as the students who has studied the content with great depth but missed out some marks due to failed regurgitation.

Mathematics in university is still regurgitation, sadly, with the exception of some courses.

I think you should find another metric to evaluate 'success' in mathematics.

__________

I'm too lazy to do the computation. Also, r != (1,1,1) + s(1,0,1) + t(0,2,2)...
 
Last edited:

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top