Help on finding domain and range~ >< (1 Viewer)

[carlytse621]

Hi, can anyone help me on this question?

What is the domain and range of:

f(x)=squ root (1-2sinx) ?

Thanks ><

 

[Mature Lamb]

-2sinx < 1

Then solve for x for domain

 

[carlytse621]

Yea I got
1/2 => sinx
sin^-1 (1/2) => x
pi/6 => x => -7pi/6
5pi/6 <= x <= 2pi
-2pi <= x <= something

but I got these answe base on graph, how can I get the solution just by working out without graph?

 

[hscishard]

The annoying problem is that x can exceed 2pi. Perhaps we need to use that general solution of trig equations? (I never got that sect. But I think you can put it here)