awesome. Just a note: if you can't balance an equation, then you got it wrong. since we can balance that one, we got the equation correct.
![](https://latex.codecogs.com/png.latex?\bg_white $ now, since we know te moles of silver nitrate AgNO_3 (0.033 moles)$ $ we can used the mole ratio that is given through the balanced equation Na_2S + 2AgNO_3 \to 2NaNO_3 +Ag_2 S $Hence 1:2\to 2:1.$ $\therefore moles Na_2S: moles NaNO_3 =1:2)
now we need to calculate the moles of sodium sulfide used in this reaction. if you don't understand, ask. glad to help
fine since you are off line i will just tell u the answer,
from the mole ration... mole of Na2S is 2 X0.033= 0.066 moles
using teh formula n=m/MM. we can work out the mass