Help pls find vector b given a = 5i +j, a dot b = 12, and the angle between a and b is 58 degrees (1 Viewer)

[Interdice]

All I managed to get out of this is that

cos(58) = 12/(5x + y)

 

[Drongoski]

Wonder if answers approx:

0.926 + 2.451 i and 1.797 - 1.906 i

 

[Interdice]

looking at the answers it is actually b = 3i -3j or b = 1.6i + 4.2j.

NEed some help figuring out how to get to the answers

 

[tywebb]

I think we will be doing this:







At this point I think you can solve it but I put the equations in wolframalpha in the following way:

5x+y=12 and cos(58 degrees)=12/sqrt(26x^2+26y^2)

and got this:

 

[Drongoski]

I got |b| = 2.618 . . . instead of 4.441 . . ..
With this correction,(multiplying my answers by 4.441/2.618) should end up with roughly the same answer.