Help with Polynomials question ! (1 Viewer)

[youngsky]

guys if you know how to do this please do it and include the process

thanks

 

[J2good4u]

basically all you need to do is apply the remainder theorem. So all you do is sub in x=1 into the equation so you get:
(1)^4 + p(1)^3 +q(1) + 1
= 1+p+q+1
= p+q+2
and we know that the remainder is 3 i.e. Q(x) = 3 therefore p+q+2 = 3...(1)
Do the same thing but now sub in x= -2 to get:
-8p-2q+17. we know that the remainder is -3 i.e. Q(x)= -3 therefore -8p-2q+17=-3...(2)

Then you just solve these two equations simultaneously

 

[youngsky]

i got the bit up to x=-2, how did you get the 17?

 

[J2good4u]

so you put x=-2:
(-2)^4 + p(-2)^3 + q(-2) + 1
= 16-8p-2q+1
= -8p-2q+17

 

[youngsky]

thanks! didn't see that, haha

 

[J2good4u]

No problems your welcome

 

[youngsky]

hey, can anybody solve this one as well?

I got up to a + b = 21 but can't get any further :/

 

[Nws m8]

fkin sub in the values , get two fkin equations, solve em simultaneously brah
like wtf?

 

[Nws m8]

sub in 3 and make the eq = 0

sub in 1 and make eq = - 8

fkin solve em simult. brah :!

 

[Nws m8]

fkin poly brah , fkin make me rage brah hahahahhaha sory bout that, did u get it though?

 

[youngsky]

thanks

EDIT: yeah i got it, forgot about the other factor

 

[mraznboy]

Lol maths in focus

 

[Timothy6340]

isnt this 3u

 

[Nws m8]

isnt this 3u

fahk bro, dnt cal it 3u, this piss easy question is like fkin geno