how are these possible (1 Viewer)

[mouse]

help!

how are these possible:

(.4 + .1) / (.4 + .2) = 2 1/3

and

140/1 = .5Y - 10(.1) = 282

they are two seperate problems.

thanks!

 

[:: ck ::]

fcuk not this again.........

 

[turtle_2468]

for the last time.. this is not 4U. please please post it in the extracurricular board
or the commerce board
or the uni board
but not here...

 

[~*HSC 4 life*~]

what? is it maths? what is it?

ahhhh!

 

[Collin]

Originally posted by ~*HSC 4 life*~
what? is it maths? what is it?

ahhhh!

No ylimE, it's Law.

 

[KeypadSDM]

Originally posted by mouse
help!

how are these possible:

(.4 + .1) / (.4 + .2) = 2 1/3

and

140/1 = .5Y - 10(.1) = 282

they are two seperate problems.

thanks!

Sqrt[1] = Sqrt[-1 * -1]
1 = Sqrt[-1] * Sqrt[-1]
1 = i * i
-1 = 1
2 = 0
1 = 0

From there:
.4 = 0, .1 = 0, .2 = 0, 7 = 0, 2 = 0
:.
.4 + .1 - 7 = 0
.4 + .1 = 7
:.
.4 + .2 - 3 = 0
.4 + .2 = 3
:.(.4 + .1) / (.4 + .2) = 7/3
:. (.4 + .1) / (.4 + .2) = 2 1/3

Ask a stupid question ...

 

[snoopwogg]

Sqrt[1] = Sqrt[-1 * -1]
1 = Sqrt[-1] * Sqrt[-1]
1 = i * i
-1 = 1
2 = 0
1 = 0



OK I have a few questions about this
FIRSTLY .. are you implying that maths is WRONG??

SECONDLY... 1 = Sqrt[-1] * Sqrt[-1] (from above)
heres where i think youre wrong...
we know that i*i = -1.. therefore implying that i = +/- sqrt [-1]
so from there...
1 = +/- Sqrt[-1] *+/- Sqrt[-1] Squaring both sides, we get
1 = -1 * -1
1 = 1
... did i do anything wrong here??

 

[stupid idiot]

Re: Re: how are these possible

Originally posted by KeypadSDM
Sqrt[1] = Sqrt[-1 * -1]
1 = Sqrt[-1] * Sqrt[-1]
1 = i * i
-1 = 1
2 = 0
1 = 0

From there:
.4 = 0, .1 = 0, .2 = 0, 7 = 0, 2 = 0
:.
.4 + .1 - 7 = 0
.4 + .1 = 7
:.
.4 + .2 - 3 = 0
.4 + .2 = 3
:.(.4 + .1) / (.4 + .2) = 7/3
:. (.4 + .1) / (.4 + .2) = 2 1/3

Ask a stupid question ...

How original... thats what i call creativity.

 

[CrashOveride]

what is it anyway

 

[Estel]

I think people aren't taking Keypad's post (which I think was quite funny given the question) very well...

 

[Heinz]

Originally posted by KeypadSDM
Sqrt[1] = Sqrt[-1 * -1]
1 = Sqrt[-1] * Sqrt[-1]
1 = i * i
-1 = 1
2 = 0
1 = 0

Reminds me of the fortstreet 2003 4u trial.

 

[+Po1ntDeXt3r+]

ROFL @ keypad.. too much time on ure hands..
classic

 

[sammeh]

another of those fun little ideas - like proving that .99999... = 1 by letting using 1/3 = .33333...

in answer to the question you pose in the topic - no. altho keypad already pointed that out.

you cant use maths to make to unequivalent values equal. anyone who tells you otherwise is simply wrong.

 

[Affinity]

Re: Re: how are these possible

mm 0.99999.... and 1.00000000 are both decimal expansions of 1.. nothing's wrong there. (there must be something between 2 different real numbers)

Originally posted by KeypadSDM
Sqrt[1] = Sqrt[-1 * -1]
1 = Sqrt[-1] * Sqrt[-1]
1 = i * i
-1 = 1
2 = 0
1 = 0

From there:
.4 = 0, .1 = 0, .2 = 0, 7 = 0, 2 = 0
:.
.4 + .1 - 7 = 0
.4 + .1 = 7
:.
.4 + .2 - 3 = 0
.4 + .2 = 3
:.(.4 + .1) / (.4 + .2) = 7/3
:. (.4 + .1) / (.4 + .2) = 2 1/3

Ask a stupid question ...

And get a stupid answer

 

[KeypadSDM]

Hmph. It's not a stupid answer. It's a good answer.

x = 0.999...
10x = 9.9999...
10x - x = 9x = 9
x = 1

 

[gman03]

Ha.. false implies true all the way

Go Discrete

 

[McLake]

(x+x)(x-x)=x(x-x)
x+x=x

/ by 0 can slip you up easily in algebra ...

 

[Slidey]

/0 is good for the soul.

 

[nick1048]

>.< I Dun't Noe Whachu Talkin Boutz

 

[Slidey]

Dividing by zero - it makes me feel good.