How do I do this q (1 Viewer)

yashbb · Oct 10, 2021

I also posted what I have so far

Lith_30 · Oct 10, 2021

Since the ball was launched horizontally $u_y=0$ , we know that $a_y=-9.81$ and $s_y=-1.3$ and we are tying to solve for t.
possible methods are:

Finding velocity using the equation $v^2=u^2+2as$ then subbing velocity into $v=u+at$ to find time
or
subbing the values into $s=ut+\frac{1}{2}at^2$ , and then solving for t using quadratic formula

yashbb · Oct 10, 2021

Lith_30 said:
Since the ball was launched horizontally $u_y=0$ , we know that $a_y=-9.81$ and $s_y=-1.3$ and we are tying to solve for t.
possible methods are:

Finding velocity using the equation $v^2=u^2+2as$ then subbing velocity into $v=u+at$ to find time
or
subbing the values into $s=ut+\frac{1}{2}at^2$ , and then solving for t using quadratic formula

THANK YOU SO MUCH

How do I do this q (1 Viewer)

yashbb

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