• Congratulations to the Class of 2024 on your results!
    Let us know how you went here
    Got a question about your uni preferences? Ask us here

How do I know if this is a right angled triangle? (1 Viewer)

BlueGas

Well-Known Member
Joined
Sep 20, 2014
Messages
2,448
Gender
Male
HSC
N/A
Basically I was trying to figure out the area for this triangle and I couldn't tell it was a right angled triangle after I looked at the answers, how would I know if this is a right angled triangle?

 

nisak

Member
Joined
Jul 2, 2015
Messages
34
Gender
Female
HSC
2015
Basically I was trying to figure out the area for this triangle and I couldn't tell it was a right angled triangle after I looked at the answers, how would I know if this is a right angled triangle?

the second part of the question tells you to the find the perpendicular distance so you use that to find the area and then you find the distance from A to C to then to A=0.5bh
 

kawaiipotato

Well-Known Member
Joined
Apr 28, 2015
Messages
463
Gender
Undisclosed
HSC
2015
It wouldn't be. It's right angled if the two lines are perpedicular ie. their gradients multiplied equal -1
The second part made you find the perpendicular distance (the 'length' of the line when you draw it from B connecting to line AC at a right angle) which will then split the triangle into two (not necessarily equal) right angled triangles
 
Last edited:

Flop21

Well-Known Member
Joined
May 12, 2013
Messages
2,807
Gender
Female
HSC
2015
Pythagoras theorem. c^2=a^2+b^2. If the sides of the triangle (distance formula) satisfy pythagoras theorem, then it's a right angled triangle.
 

Drsoccerball

Well-Known Member
Joined
May 28, 2014
Messages
3,650
Gender
Undisclosed
HSC
2015
You don't need to know what triangle it is if you are given the perpendicular distance.
 

sharoooooo

Active Member
Joined
Mar 30, 2015
Messages
297
Location
Online
Gender
Undisclosed
HSC
2015
just get the gradient for AB and then the gradient for BC.

then multiply the gradients together, and it should =-1.

hence, perpendicular (right angle)
 

Users Who Are Viewing This Thread (Users: 0, Guests: 1)

Top