Carrotsticks
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Addition for independent events (usually requires addition of 'cases')Hmm this is only happening in 2u probability but initially I was rote learning, as compared to now where I actually think about the question. Basically I'll get straight to the point:
1. Question asks me to find probability of getting x jelly beans from two packets.
2. I get confused whether to use addition or product rule.
That's it.
ie: Probability of getting at most 2 distinct red marbles from a bag containing N marbles = P(no red) + P(1 red) + P(2 red) etc etc...
Product for dependent events (if we are doing this all in 1 action, you usually multiply the probability of each action)
ie: Probability of getting 2 distinct red marbles and then 2 distinct blue marbles = P(one red) x P(one red) x P(one blue) x P(one blue)