F fabl Member Joined Aug 7, 2014 Messages 56 Gender Male HSC 2014 Aug 24, 2014 #1 how to find points of intersection of px + qy =1 and qx + py =1 and explain why the lines intersect on line y =x ?
how to find points of intersection of px + qy =1 and qx + py =1 and explain why the lines intersect on line y =x ?
youngsky poof Joined Sep 23, 2012 Messages 203 Location Sydney Gender Male HSC 2014 Aug 25, 2014 #2 Let: px + qy = qx + py (as both are equal to 1) py - qy = px - qx y(p-q) = x(p-q) Cancelling common factor (p-q), you get y = x. Hence although p and q are variable, both lines will nevertheless intersect on the line y = x.
Let: px + qy = qx + py (as both are equal to 1) py - qy = px - qx y(p-q) = x(p-q) Cancelling common factor (p-q), you get y = x. Hence although p and q are variable, both lines will nevertheless intersect on the line y = x.
B braintic Well-Known Member Joined Jan 20, 2011 Messages 2,137 Gender Undisclosed HSC N/A Aug 26, 2014 #3 fabl said: how to find points of intersection of px + qy =1 and qx + py =1 and explain why the lines intersect on line y =x ? Click to expand... Or more conventionally: Mult 1st by p: (p^2)x+pqy=p Mult 2nd by q: (q^2)x+pqy=q Subtract: (p^2 - q^2) x = (p-q) (p-q)(p+q)x = (p-q) x=1/(p+q) Instead multiplying the 1st by q and the 2nd by p gives y = 1/(p+q) They intersect on y=q because they are inverse relations. That is, the roles of x and y have been swapped.
fabl said: how to find points of intersection of px + qy =1 and qx + py =1 and explain why the lines intersect on line y =x ? Click to expand... Or more conventionally: Mult 1st by p: (p^2)x+pqy=p Mult 2nd by q: (q^2)x+pqy=q Subtract: (p^2 - q^2) x = (p-q) (p-q)(p+q)x = (p-q) x=1/(p+q) Instead multiplying the 1st by q and the 2nd by p gives y = 1/(p+q) They intersect on y=q because they are inverse relations. That is, the roles of x and y have been swapped.